Swift

Question

我创建了一个从英语单词到西班牙语单词的迷你翻译。我想使用 englishArray.plist 而不是我的 englishArray = ["the cat"] 如何创建它？

我还使用 localizable.strings 检索 "el gato" 的值 "the cat"，但我想从 englishArray.plist

检索该值

我从这个开始，但不确定我是否走在正确的道路上

let path = NSBundle.mainBundle().pathForResource("englishArray", ofType: "plist") 
let plistEnglishArray = NSArray(contentsOfFile: path!)

这是我的其余代码：

var englishArray: [String] = ["rainbow", "boots", "heart", "leaf", "umbrella", "tired", "angry", "cry", "the cat" ]


override func viewDidLoad() {
    super.viewDidLoad()
    // Do any additional setup after loading the view, typically from a nib.

    self.translateTextField.delegate = self
    picker.delegate = self
    picker.dataSource = self
}

override func didReceiveMemoryWarning() {
    super.didReceiveMemoryWarning()
    // Dispose of any resources that can be recreated.
}

@IBAction func translateButtonTapped(sender: UIButton) {

    let emptyString = self.translateTextField.text

    if (emptyString!.isEmpty) {

        print("please enter a word")

    }

    for transIndex in englishArray.indices {
        if englishArray[transIndex] == emptyString!.lowercaseString {

            //englishArray

            //translateLabel.text = "\(spanishArray[transIndex])"
            translateLabel.text = NSLocalizedString(emptyString!.lowercaseString, comment:"")


            print(emptyString)
            return

        }
    }
}

Answer 1

将您的 root 对象更改为 Array，然后

var myEnglishArray: [String] = []
if let URL = NSBundle.mainBundle().URLForResource("englishArray", withExtension: "plist") {
      if let englishFromPlist = NSArray(contentsOfURL: URL) as? [String] {
        myEnglishArray = englishFromPlist
      }
    }

Answer 2

这将读取您的包中名为 "englishArray.plist" 的资源，并将其存储在不可变变量 english 中。这将是一个可选的，您应该在使用前进行测试。

它使用闭包来读取文件和 return 数组，这使您可以使用不可变值而不是可以更改的可变变量。尽可能使用不可变变量是个好主意 - 它们可以提高稳定性。

import Foundation

let english:[String]? = {
  guard let URL = NSBundle
    .mainBundle()
    .URLForResource("englishArray", withExtension: "plist") else {
      return nil
  }
  return NSArray(contentsOfURL: URL) as? [String]
}()

Answer 3

这是 swift 3 的解决方案。对于此解决方案，您不需要更改 plist 结构中的类型（保持字典、数组原样）。另请注意，由于您的数组在 plist 中的名称也是 englishArray，因此第二个 if 语句中的（键值）参数也是 englishArray。

var myEnglishArray: [String] = []
   if let URL = Bundle.main.url(forResource: "englishArray", withExtension: "plist") {
      guard let englishFromPlist = NSDictionary(contentsOf: URL) else { return [] }
      if let englishArray = englishFromPlist.value(forKey: "englishArray") as? [String] {
         for myEnglish in englishArray {
            myEnglishArray.append(myEnglish)
         }
      }
   }

Answer 4

Swift 4

您可以使用纯 swift 类型的 Codable。

首先从bundle加载Plist文件然后使用PropertyListDecoder

完整代码-

    func setData() {
        // location of plist file
        if let settingsURL = Bundle.main.path(forResource: "JsonPlist", ofType: "plist") {

            do {
                var settings: MySettings?
                let data = try Data(contentsOf: URL(fileURLWithPath: settingsURL))
                    let decoder = PropertyListDecoder()
                settings = try decoder.decode(MySettings.self, from: data)
                print("array  is \(settings?.englishArray ?? [""])")//prints array  is ["Good morning", "Good afternoon"]


            } catch {
                print(error)
            }
        }
    }
}
struct MySettings: Codable {

    var englishArray: [String]?

    init(from decoder: Decoder) throws {
        let values = try decoder.container(keyedBy: CodingKeys.self)
        englishArray = try values.decodeIfPresent([String].self, forKey: .englishArray)

    }
}

Answer 5

Swift 4

最简单的方法是

    let url = Bundle.main.url(forResource: "Sounds", withExtension: "plist")!
    let soundsData = try! Data(contentsOf: url)
    let myPlist = try! PropertyListSerialization.propertyList(from: soundsData, options: [], format: nil)

对象 myPlist 是数组或字典，以您用作 plist 的基础为准。

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