在我的例子中，如何获得 table 中两个不同列的排名？

Question

所以我有一个名为 db_points 的 table。

----------------------------------------
| Name    | Points | SPoints | RPoints |
----------------------------------------
| Max     | 240    | 50      | 1242    |
| Alvin   | 600    | 123     | 3012    |
| Amanda  | 234    | 1000    | 132     |
| Angela  | 50     | 514     | 4023    |
| Rudolph | 2000   | 230     | 1232    |
----------------------------------------

我需要基于TPoints（Points+SPoints），Points，SPoints排序的排名，基于RPoints和RPoints的排名。

对于安吉拉、鲁道夫或阿曼达来说，这看起来像下面这样。

--------------------------------------------------------------------
| RankT   | Name    | TPoints | Points | SPoints | RankR | RPoints |
--------------------------------------------------------------------
| 4       | Angela  | 564     | 50     | 514     | 5     | 4023    |
| 1       | Rudolph | 2230    | 2000   | 230     | 2     | 1232    |
| 2       | Amanda  | 1234    | 234    | 1000    | 1     | 132     |
--------------------------------------------------------------------

如您所见，排名不同。 TPoints越高，RankT越好； RPoints越低，RankR越好。

但是我需要在一个 SQL 查询中得到它。这是我到目前为止得到的：

select  Rank,
        Name,
        TPoints,
        Points,
        SPoints
        RankR
        from    (select (@pos := @pos+1) pos,
            (@rank := IF(@prev = TPoints,@rank,@pos)) Rank,
            TPoints,
            Points,
            SPoints,
            Name,
            RPoints,
            select @rownum:=@rownum + 1 as RankR,t.*
            from    (select (@prev := SPoints+Points) TPoints,
                                SPoints,
                                Points,
                                Name,
                                RPoints
                                from db_points
                                order by TPoints desc)

                                as ll,
                                (select RPoints,
                                Name
                                from db_points where RPoints > 0 order by RPoints ASC) t,(SELECT @rownum := 0)
                                r)
                        as l
                where Name = '%s';

希望这是可以理解的。

到目前为止，我有两个工作查询需要放入其中一个

select Rank, Name, TPoints, Points, SPoints from (select (@pos := @pos+1) pos, (@rank := IF(@prev = TPoints,@rank,@pos)) Rank, TPoints, Points, SPoints, Name from (select (@prev := SPoints+Points) TPoints, SPoints, Points, Name from db_points order by TPoints desc) as ll) as l where Name = '%s';

还有这个

select  RankR
                from    (select @rownum:=@rownum + 1 as RankR,t.*
                        from    (select RPoints,
                                        Name
                                        from db_points where RPoints > 0 order by RPoints ASC) t,(SELECT @rownum := 0)
                                r)
                        a

                where Name='%s';

希望你能阅读代码，我在格式化 mysql 代码方面很糟糕。

Answer 1

请试一试

SELECT @rankT:=@rankT+1 as RankT,
       T.*
FROM
  (SELECT Name,
         (Points+Spoints) as TPoints,
         Points,
         Spoints,
         @rankR := @rankR + 1 as RankR,
         Rpoints
  FROM db_points p, (SELECT @rankR:=0)initialR
  ORDER BY Rpoints ASC
  )T,(SELECT @rankT:=0)intialT
ORDER BY TPoints DESC

sqlfiddle

然后您可以将整个查询作为子查询并执行外部 select 来查找 WHERE name like '%s'

在我的例子中，如何获得 table 中两个不同列的排名？

How to get the ranks of two different colums in a table in my case?

mysql