jq - 合并两个 JSON 文件时出错 "cannot be multiplied"

jq - error when merging two JSON files "cannot be multiplied"

我有两个文件,其中包含一些 JSON。

File1 - 有些值可以是字符串,有些可能为空,VolumeId 始终设置。

[
  {
    "VolumeId": "vol-xxxxxxx1",
    "Tag1": "Tag1Value",
    "Tag2": "Tag2Value",
    "Tag3": "Tag3Value",
    "Tag4": "Tag4Value",
    "Tag5": "Tag5Value",
    "Tag6": "Tag6Value"
  },
  {
    "VolumeId": "vol-xxxxxxx2",
    "Tag1": "Tag1Value",
    "Tag2": "null",
    "Tag3": "null",
    "Tag4": "Tag4Value",
    "Tag5": "null",
    "Tag6": "Tag6Value"
  },
  {
    "VolumeId": "vol-xxxxxxx3",
    "Tag1": "null",
    "Tag2": "null",
    "Tag3": "null",
    "Tag4": "null",
    "Tag5": "null",
    "Tag6": "null"
  }
]

File2 - VolumeId 将始终与 File1 中的匹配,Tag7 可能为空也可能不为空。

[
  {
    "VolumeId": "vol-xxxxxxx1",
    "Tag7": "Tag7Value"
  },
  {
    "VolumeId": "vol-xxxxxxx2",
    "Tag7": "Tag7Value"
  },
  {
    "VolumeId": "vol-xxxxxxx3",
    "Tag7": "null"
  }
]

我需要将这些组合成一个 JSON 数组:

[
  {
    "VolumeId": "vol-xxxxxxx1",
    "Tag1": "Tag1Value",
    "Tag2": "Tag2Value",
    "Tag3": "Tag3Value",
    "Tag4": "Tag4Value",
    "Tag5": "Tag5Value",
    "Tag6": "Tag6Value",
    "Tag7": "Tag7Value"
  },
  {
    "VolumeId": "vol-xxxxxxx2",
    "Tag1": "Tag1Value",
    "Tag2": "null",
    "Tag3": "null",
    "Tag4": "Tag4Value",
    "Tag5": "null",
    "Tag6": "Tag6Value",
    "Tag7": "Tag7Value"
  },
  {
    "VolumeId": "vol-xxxxxxx3",
    "Tag1": "null",
    "Tag2": "null",
    "Tag3": "null",
    "Tag4": "null",
    "Tag5": "null",
    "Tag6": "null",
    "Tag7": "null"
  }
]

我在尝试使用以下命令时遇到错误:

jq -s '.[0] * .[1]' /path/to/file1 /path/to/file2
array ([{"VolumeId...) and array ([{"VolumeId...) cannot be multiplied

感谢任何帮助。

你应该做什么:

文件1

{
  "vol-xxxxxxx1": {
    "Tag1": "Tag1Value",
    "Tag2": "Tag2Value",
    "Tag3": "Tag3Value",
    "Tag4": "Tag4Value",
    "Tag5": "Tag5Value",
    "Tag6": "Tag6Value"
  },
  "vol-xxxxxxx2": {
    "Tag1": "Tag1Value",
    "Tag2": "null",
    "Tag3": "null",
    "Tag4": "Tag4Value",
    "Tag5": "null",
    "Tag6": "Tag6Value"
  },
  "vol-xxxxxxx3": {
    "Tag1": "null",
    "Tag2": "null",
    "Tag3": "null",
    "Tag4": "null",
    "Tag5": "null",
    "Tag6": "null"
  }
}

文件2

{
  "vol-xxxxxxx1": {
    "Tag7": "Tag7Value"
  },
  "vol-xxxxxxx2": {
    "Tag7": "Tag7Value"
  },
  "vol-xxxxxxx3": {
    "Tag7": "null"
  }
}

现在命令

jq -s '.[0] * .[1]' /path/to/file1 /path/to/file2

给出以下内容:

{
  "vol-xxxxxxx1": {
    "Tag1": "Tag1Value",
    "Tag2": "Tag2Value",
    "Tag3": "Tag3Value",
    "Tag4": "Tag4Value",
    "Tag5": "Tag5Value",
    "Tag6": "Tag6Value",
    "Tag7": "Tag7Value"
  },
  "vol-xxxxxxx2": {
    "Tag1": "Tag1Value",
    "Tag2": "null",
    "Tag3": "null",
    "Tag4": "Tag4Value",
    "Tag5": "null",
    "Tag6": "Tag6Value",
    "Tag7": "Tag7Value"
  },
  "vol-xxxxxxx3": {
    "Tag1": "null",
    "Tag2": "null",
    "Tag3": "null",
    "Tag4": "null",
    "Tag5": "null",
    "Tag6": "null",
    "Tag7": "null"
  }
}

我假设您想将具有相同 .VolumeId 的所有条目合并为一个。为此,首先我们将 flatten 对象数组转换为对象数组。然后,我们group_by(.VolumeId)。最后,我们 map 遍历每个组并 reduce 通过计算其所有元素的乘积。最终结果如下所示:

jq -s 'flatten | group_by(.VolumeId) | map(reduce .[] as $x ({}; . * $x))' /path/to/file1 /path/to/file2