Rails 表单发送的邮件视图模板传值

Question

这是我第一次尝试使用 rails 邮件程序发送电子邮件。但是，我能够发送普通电子邮件，但是当我尝试传递由表单发送的登录用户 (current_user) 名称和参数值时，我收到了错误消息。未定义的方法 'params'.

payment_mailer.rb

class PaymentMailer < ApplicationMailer
    def success(user)
        mail(to: "#{user.first_name} #{user.last_name} <#{user.email}>", subject: "Payment Successful")
    end
end

success.html.erb

<div class = "col-sm-12">
          <h1>Payment Successful</h1>
          <p>Dear <%= user.first_name %>, Thank you for being a part of our system<br>
            Your invoice (#<%= params[:id] %>) has been generated.
          </p>
        </div>
        <div class = "clearfix"></div>
        <div class = "col-sm-6">
          <table class = "table">
            <thead>
              <tr>
                <th>Paid Ammount</th>
                <th>Card Transaction Fee (2.9% + 0.30)</th>
                <th>Credited Ammount</th>
              </tr>
            </thead>
            <tbody>
              <tr>
                <td>&euro;<%= params[:amount] %></td>
                <td></td>
                <td></td>
              </tr>
            </tbody>
            <h3>Total credited amount in your Account is: </h3>
          </table>
        </div>
        <div class = "clearfix"></div>
      </div>

payment_controller.rb

amount = params[:amount]
@user = current_user
netamt =  (amount.to_f - ((amount.to_f*2.9)/100 + 0.30))
payment = @user.payments.create(:amount => netamt, :method => "Card", :txn_code => params[:stripeToken])
@user.update_attribute(:balance, @user.balance+netamt)
PaymentMailer.success(current_user).deliver_now

请指导我。

Answer 1

控制器对象，例如 params 或 current_user 未在您的邮件程序上下文中定义。

您需要为用户设置这些值，或者将它们作为附加参数传递到您的邮件程序方法中。您还需要分配实例变量以在邮件视图中访问这些值（与将控制器中定义的实例变量传递给 ActionView 的原理相同）。

class PaymentMailer < ApplicationMailer
    def success(user, invoice_id, amount)
        @invoice_id = invoice_id
        @amount = amount

        mail(to: "#{user.first_name} #{user.last_name} <#{user.email}>", subject: "Payment Successful")
    end
end

但是，amount、id 和 user 似乎都是 payment 对象的变量，所以这听起来像是您真正应该成为的对象将 payment 传递给 success 方法，而不是 current_user。这可能吗？

Answer 2

付款后在你的支付控制器中更改，就这样

PaymentMailer.success(payment).deliver_now

然后在您的邮件程序中执行

class PaymentMailer < ApplicationMailer
  def success(payment)
    @payment = payment
    @user = payment.user
    mail(to: "#{@user.first_name} #{@user.last_name} <#{@user.email}>", subject: "Payment Successful")
  end
end

并在您的邮件模板中使用

@payment.id #for payment id

@payment.amount #for amount

@user.first_name #for user name

Rails 表单发送的邮件视图模板传值

Rails mailer view template pass value send by a form

ruby

ruby-on-rails

actionmailer

mailer