使用 .distinct() 时 Django ORM 多次返回相同的值
Django ORM returning the same values multiple times when using .distinct()
在一组对象上使用 .distinct()
时,相同的值会一遍又一遍地重复,这违背了使用 .distinct()
的目的
我正在从事的项目中的一个示例:
In [5]: Section.objects.filter(module=15).values('section').distinct()
Out[5]: [{'section': '1'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, '...(remaining elements truncated)...']
为什么它返回每个值而不是仅返回不同的值?
作为参考,这是我的模型:
class Section(models.Model):
module = models.ForeignKey(Module, on_delete=models.CASCADE)
title = models.CharField(max_length=400)
section = models.CharField(max_length=3)
topic = models.CharField(max_length=3)
subtopic = models.CharField(max_length=3)
subsubtopic = models.CharField(max_length=3)
language = models.CharField(max_length=2)
def __str__(self):
return self.sectionid() + " - " + self.title
def sectionid(self):
return self.module.moduleid + ": " + self.justsectionid()
def justsectionid(self):
return self.section + "." + self.topic + "." + self.subtopic + \
self.subsubtopic + "-" + self.language
class Meta:
ordering = ['section', 'topic', 'subtopic', 'subsubtopic', 'language']
Django ORM .distinct()
存在问题,如果您使用元排序,就会发生此行为。为了使其按预期工作,您需要将排序重置为默认值。您可以通过对 .order_by()
的空白调用来执行此操作,如下所示:
In [6]: Section.objects.filter(module=15).order_by().values('section').distinct()
Out[6]: [{'section': '1'}, {'section': '2'}, {'section': '3'}]
在一组对象上使用 .distinct()
时,相同的值会一遍又一遍地重复,这违背了使用 .distinct()
我正在从事的项目中的一个示例:
In [5]: Section.objects.filter(module=15).values('section').distinct()
Out[5]: [{'section': '1'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, {'section': '2'}, '...(remaining elements truncated)...']
为什么它返回每个值而不是仅返回不同的值?
作为参考,这是我的模型:
class Section(models.Model):
module = models.ForeignKey(Module, on_delete=models.CASCADE)
title = models.CharField(max_length=400)
section = models.CharField(max_length=3)
topic = models.CharField(max_length=3)
subtopic = models.CharField(max_length=3)
subsubtopic = models.CharField(max_length=3)
language = models.CharField(max_length=2)
def __str__(self):
return self.sectionid() + " - " + self.title
def sectionid(self):
return self.module.moduleid + ": " + self.justsectionid()
def justsectionid(self):
return self.section + "." + self.topic + "." + self.subtopic + \
self.subsubtopic + "-" + self.language
class Meta:
ordering = ['section', 'topic', 'subtopic', 'subsubtopic', 'language']
Django ORM .distinct()
存在问题,如果您使用元排序,就会发生此行为。为了使其按预期工作,您需要将排序重置为默认值。您可以通过对 .order_by()
的空白调用来执行此操作,如下所示:
In [6]: Section.objects.filter(module=15).order_by().values('section').distinct()
Out[6]: [{'section': '1'}, {'section': '2'}, {'section': '3'}]