swift 2.0 中过滤方法的第二个参数

Question

我使用以下代码在我的应用程序中搜索 tableviewcontroller。当前搜索字符串与我的 table 列表中的餐馆名称匹配。我希望 match/search 附加字符串，位置与我的代码。如何向此功能添加位置

餐厅名称变量 - restaurant.name ,
餐厅位置变量 - restaurant.location

func filterContentForSearchText(searchText: String) {
        searchResults = restaurants.filter({ ( restaurant: Restaurant) -> Bool in let nameMatch = restaurant.name.rangeOfString(searchText, options:
        NSStringCompareOptions.CaseInsensitiveSearch)
        return nameMatch != nil
        })
    }

    func updateSearchResultsForSearchController(searchController: UISearchController) {
        let searchText = searchController.searchBar.text
        filterContentForSearchText(searchText!)
        tableView.reloadData()
    }

如何在我的过滤方法中添加这个附加参数？

Answer 1

试试这个。

func filterContentForSearchText(searchText: String) {
        searchResults = restaurants.filter({ ( restaurant: Restaurant) -> Bool in 

        let nameMatch = restaurant.name.rangeOfString(searchText, options:
        NSStringCompareOptions.CaseInsensitiveSearch)

        let locationMatch = restaurant.location.rangeOfString(searchText, options:
        NSStringCompareOptions.CaseInsensitiveSearch)

        return (nameMatch != nil || locationMatch != nil)
        })
    }

Answer 2

You can do like this

 func filterContentForSearchText(searchText: String) {

        searchResults = restaurants.filter({( restaurant: Restaurant) -> Bool in

          return restaurant.location.lowercaseString.containsString(searchText.lowercaseString) || restaurant.name.lowercaseString.containsString(searchText.lowercaseString)

        })

        tableView.reloadData()
      }

Delegate Method

  func updateSearchResultsForSearchController(searchController: UISearchController) {

    filterContentForSearchText(searchController.searchBar.text!)
  }

此方法将帮助您更好地搜索

swift 2.0 中过滤方法的第二个参数

second parameter for filter method in swift 2.0

swift

uisearchcontroller