Python zip() 两个列表
Python zip() two lists
我试图压缩两个长度相同的列表,但我总是收到错误
"zip object at 0x0000000002A81548" 而不是压缩列表。
filename = input("Which file do you want to open?: \n")
file = open("C:/"+ filename,'r')
movielist = []
moviename = []
moviedate = []
for line in file:
line.strip()
name = re.search('name:(.*)',line)
date = re.search('date:(.*)',line)
if name:
titel = name.group(1)
moviename.append(titel)
if date:
datum = date.group(1)
moviedate.append(datum)
print("Name of the list: ", moviename.pop(0))
movielist= zip(moviename,moviedate)
print(movielist)
print("Number of movies: " , len(moviename))
movielist= list(zip(moviename,moviedate))
在Python 2 zip
returns 一个列表和以上是不需要的。在 Python 3 中,它 returns 一个特殊的惰性 zip 对象,类似于生成器或 itertools.izip
,您需要具体化才能使用 len
。 map
.
也是如此
我试图压缩两个长度相同的列表,但我总是收到错误 "zip object at 0x0000000002A81548" 而不是压缩列表。
filename = input("Which file do you want to open?: \n")
file = open("C:/"+ filename,'r')
movielist = []
moviename = []
moviedate = []
for line in file:
line.strip()
name = re.search('name:(.*)',line)
date = re.search('date:(.*)',line)
if name:
titel = name.group(1)
moviename.append(titel)
if date:
datum = date.group(1)
moviedate.append(datum)
print("Name of the list: ", moviename.pop(0))
movielist= zip(moviename,moviedate)
print(movielist)
print("Number of movies: " , len(moviename))
movielist= list(zip(moviename,moviedate))
在Python 2 zip
returns 一个列表和以上是不需要的。在 Python 3 中,它 returns 一个特殊的惰性 zip 对象,类似于生成器或 itertools.izip
,您需要具体化才能使用 len
。 map
.