计数限制为另一个table中定义的特定值

Question

这是我拥有的 2 table

unit:

unit name    |    no. of beds
-----------------------------
unit 1       |         4
unit 2       |         3

worker:

name         |    unit name
-----------------------------
worker 1     |     unit 1
worker 2     |     unit 1
worker 3     |     unit 1
worker 4     |     unit 1
worker 5     |     unit 1
worker 6     |     unit 2

我需要计算每个单元的可用床位数量，但将每次计数限制为相应单元的床位数量。 IE。如果在 table 单元中，单元 1 定义为有 4 张床，但在 table 工人中它有 5 个工人标记到单元 1，它应该只 return 计数为 4.

这是我现在拥有的，但它是 return 的总计数，无视编号。为每个房间定义的床位。

我想要的结果是 return“2”表示可用床位的数量。如何将其合并到我的查询中？

$sql = "SELECT COUNT(*) AS 'count_worker' FROM worker WHERE (`unit_id` IS NOT NULL and `unit_id` <> '')";
$rs = CustomQuery($sql);
$data = db_fetch_array($rs);

$sql2 = "SELECT SUM(no_bed) AS 'count_vacancy' FROM unit WHERE `active` = 'yes'";
$rs2 = CustomQuery($sql2);
$data2 = db_fetch_array($rs2);

$vacancy = $data2["count_vacancy"] - $data["count_worker"];
if ($vacancy >0)
{
echo "# of beds available: " . $vacancy;
}
else 
{
echo "# of beds available: 0";
}

Answer 1

http://sqlfiddle.com/#!9/674e4/1

SELECT 
  w.unit_name, 
  if(w.cnt<=u.no_of_beds,w.cnt,u.no_of_beds)
FROM (
  SELECT count(*) cnt, unit_name
  FROM worker
  GROUP BY unit_name) w
LEFT JOIN unit u
ON w.unit_name = u.unit_name

并获得可用床位的数量 http://sqlfiddle.com/#!9/88734/2

SELECT 
  u.unit_name, 
  if(w.cnt<=u.no_of_beds,u.no_of_beds-w.cnt, IF(w.cnt IS NULL,u.no_of_beds,0)) beds_available
FROM unit u
LEFT JOIN (
  SELECT count(*) cnt, unit_name
  FROM worker
  GROUP BY unit_name) w
ON w.unit_name = u.unit_name;

计数限制为另一个table中定义的特定值

Count limit to a specific value defined in another table

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