后退按钮的监听器
Listener for BACK-button
当显示警告对话框时,我如何才能对后退按钮执行任何操作?
我必须问用户 "Do you really want discard changes?"
此时屏幕上出现输入提示对话框
你最初的问题不是很清楚你想做什么。因此,如果您想在用户在 EditText
中输入内容后按下后退按钮时显示一个对话框,那么您需要 @Override
Activity 中的 onBackPressed
方法class.
@Override
public void onBackPressed() {
// Here you want to show the user a dialog box
new AlertDialog.Builder(context)
.setTitle("Exiting the App")
.setMessage("Are you sure?")
.setPositiveButton("YES", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
// The user wants to leave - so dismiss the dialog and exit
finish();
dialog.dismiss();
}
}).setNegativeButton("NO", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
// The user is not sure, so you can exit or just stay
dialog.dismiss();
}
}).show();
}
您可以查看已接受的答案here。
但是如果您只想处理对话框本身的后退按钮按下,那么这个问题已经有了答案 - 基本上您可以像这样在对话框上设置 OnKeyListener
:
dialog.setOnKeyListener(new Dialog.OnKeyListener() {
@Override
public boolean onKey(DialogInterface arg0, int keyCode,KeyEvent event)
{
if (keyCode == KeyEvent.KEYCODE_BACK) {
/* The user pressed back button - do whatever here.
Normally you dismiss the dialog like dialog.dismiss(); */
}
return true;
}
});
查看已接受的答案here。
builder.setNegativeButton(R.string.btn_rev, new DialogInterface.OnClickListener(){
@Override
public void onClick(DialogInterface dialog, int which) {
//если что-то ввели и нажали Назад
if (edText.getText() != null) {
// onBackPressed(); //here's code for back-button
}
}
});
当显示警告对话框时,我如何才能对后退按钮执行任何操作? 我必须问用户 "Do you really want discard changes?"
此时屏幕上出现输入提示对话框
你最初的问题不是很清楚你想做什么。因此,如果您想在用户在 EditText
中输入内容后按下后退按钮时显示一个对话框,那么您需要 @Override
Activity 中的 onBackPressed
方法class.
@Override
public void onBackPressed() {
// Here you want to show the user a dialog box
new AlertDialog.Builder(context)
.setTitle("Exiting the App")
.setMessage("Are you sure?")
.setPositiveButton("YES", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
// The user wants to leave - so dismiss the dialog and exit
finish();
dialog.dismiss();
}
}).setNegativeButton("NO", new DialogInterface.OnClickListener() {
public void onClick(DialogInterface dialog, int whichButton) {
// The user is not sure, so you can exit or just stay
dialog.dismiss();
}
}).show();
}
您可以查看已接受的答案here。
但是如果您只想处理对话框本身的后退按钮按下,那么这个问题已经有了答案 - 基本上您可以像这样在对话框上设置 OnKeyListener
:
dialog.setOnKeyListener(new Dialog.OnKeyListener() {
@Override
public boolean onKey(DialogInterface arg0, int keyCode,KeyEvent event)
{
if (keyCode == KeyEvent.KEYCODE_BACK) {
/* The user pressed back button - do whatever here.
Normally you dismiss the dialog like dialog.dismiss(); */
}
return true;
}
});
查看已接受的答案here。
builder.setNegativeButton(R.string.btn_rev, new DialogInterface.OnClickListener(){
@Override
public void onClick(DialogInterface dialog, int which) {
//если что-то ввели и нажали Назад
if (edText.getText() != null) {
// onBackPressed(); //here's code for back-button
}
}
});