使用左外连接和 on 子句从具有公共列的两个不同表中检索数据

Retrieving data from two different tables with common column using left outer join and on clause

伙计们,我有两个不同的 tables。

Table-1:

contract-id | contract-date
  1         | 01-05-2016
  1         | 01-06-2016
  1         | 01-07-2016
  2         | 01-01-2016
  2         | 01-02-2016
  3         | 01-05-2016
  3         | 01-06-2016

Table-2:

invoice-number|contract-id|invoice-from-date|invoice-to-date
 1            |1          |01-05-2016       |31-05-2016
 2            |1          |15-05-2016       |31-05-2016
 3            |1          |25-05-2016       |31-05-2016

我的要求是,我必须显示当月从 table-1 开始的所有合同,并且我必须显示从 [=30] 开始的这些合同的发票数量=]-2。如果有任何发票,它应该显示它的计数或简单地显示为零。预期的答案是:

contract-id|counts
 1         |3
 3         |0

contract-id: 1 的计数是 3,因为我为当月开了三张发票,而 contract-id: 3 的计数是 0,因为我没有为此开过任何发票。并且缺少 contract-id:2 ,因为它不属于当前月份。

这是我试过的:

    select cbm_contract_period_value_split.contract_id,
count(cbm_contract_invoice_request.contract_id),
cbm_contract_period_value_split.contract_date
from cbm_contract_period_value_split
left outer join cbm_contract_invoice_request
on cbm_contract_period_value_split.contract_id = cbm_contract_invoice_request.contract_id
and MONTH(cbm_contract_period_value_split.contract_date) = MONTH(CURDATE())
and MONTH(cbm_contract_invoice_request.invoice_for_the_period_of_from_date) = MONTH(CURDATE())

我已经发布了这个问题,但现在我发布的是带有我得到的答案的编辑版本。然而,我没有得到想要的答案。怎么了,我该怎么办?

试试这个。我想你需要一个 GROUP BY 并且我在 WHERE 中过滤掉不是当前月份的行。

select pvs.contract_id,
       count(ir.contract_id) as counts,
       pvs.contract_date
from cbm_contract_period_value_split as pvs
left join cbm_contract_invoice_request as ir
on pvs.contract_id = ir.contract_id
and MONTH(ir.invoice_for_the_period_of_from_date) = MONTH(CURDATE())
WHERE MONTH(pvs.contract_date) = MONTH(CURDATE())
GROUP BY pvs.contract_id,pvs.contract_date

http://sqlfiddle.com/#!9/e5f08c/9

结果

contract_id     counts  contract_date
1               3       May, 01 2016 00:00:00
3               0       May, 01 2016 00:00:00
SELECT Table-1.contract_id, Table-1.contract-date, COUNT(*) AS count FROM Table-2 LEFT JOIN Table-1 ON Table-1.contract_id =  Table-2.contract_id WHERE MONTH(Table-1.contract-date) = MONTH(CURDATE()) GROUP BY Table-1.contract_id

试试这个查询..

SELECT 
  t1.`contract-id`,
  (    
    CASE      
      WHEN t2.`contract-id` IS NULL 
      THEN 0 
      ELSE COUNT(*) 
    END
  ) AS counts 
FROM
  t1 
  LEFT JOIN t2 
    ON t1.`contract-id` = t2.`contract-id` 
WHERE MONTH(`contract-date`) = MONTH(CURDATE()) 
GROUP BY t2.`contract-id` 
ORDER BY t1.`contract-id`,`contract-date` ;

FIDDLE