如何增强回调处理程序 CXF 拦截器方法

Question

我在spring bean配置文件中做了一个WSS4JInInterceptor如下

    <?xml version="1.0" encoding="UTF-8"?>
    <beans xmlns="http://www.springframework.org/schema/beans"
        xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jaxws="http://cxf.apache.org/jaxws"
        xmlns:jaxrs="http://cxf.apache.org/jaxrs"
        xsi:schemaLocation="http://cxf.apache.org/jaxws 
                            http://cxf.apache.org/schemas/jaxws.xsd
                            http://www.springframework.org/schema/beans 
                            http://www.springframework.org/schema/beans/spring-beans.xsd
                            http://cxf.apache.org/jaxrs 
                            http://cxf.apache.org/schemas/jaxrs.xsd">

        <jaxws:endpoint id="book"
            implementor="net.ma.soap.ws.endpoints.IBookEndPointImpl" address="/bookAuth">
            <jaxws:inInterceptors>
                <bean class="org.apache.cxf.binding.soap.saaj.SAAJInInterceptor"></bean>
                <bean class="org.apache.cxf.ws.security.wss4j.WSS4JInInterceptor">
                    <constructor-arg>
                        <map>
                            <entry key="action" value="UsernameToken" />
                            <entry key="passwordType" value="PasswordText" />
                            <entry key="passwordCallbackClass" value="net.ma.soap.ws.service.ServerPasswordCallback"></entry>
                        </map>
                    </constructor-arg>
                </bean>
            </jaxws:inInterceptors>
        </jaxws:endpoint>
    </beans>

ServerPasswordCallBack.java 看起来像下面的

    package net.ma.soap.ws.service;

    import java.io.IOException;
    import java.util.ResourceBundle;
    import javax.security.auth.callback.Callback;
    import javax.security.auth.callback.CallbackHandler;
    import javax.security.auth.callback.UnsupportedCallbackException;
    import org.apache.wss4j.common.ext.WSPasswordCallback;

    public class ServerPasswordCallback implements CallbackHandler {

        private static final String BUNDLE_LOCATION = "zuth";
        private static final String PASSWORD_PROPERTY_NAME = "auth.manager.password";
        private static String password;

        static {
            final ResourceBundle bundle = ResourceBundle.getBundle(BUNDLE_LOCATION);
            password = bundle.getString(PASSWORD_PROPERTY_NAME);
        }

        @Override
        public void handle(Callback[] callbacks) throws IOException, UnsupportedCallbackException {
            WSPasswordCallback pc = (WSPasswordCallback) callbacks[0];
            pc.setPassword(password);
        }
    }

通过密码验证，一切正常。

我想知道是否有任何其他方法可以增强 handle(Callback) 方法，使其更加复杂，以便能够检查不止一个参数，例如，如果我可以让它检查访问令牌，那就更好了。

密码属性在zuth_fr_FR.properties文件中定义如下

auth.manager.password=纳贾

Answer 1

如果您想对您的用户名和令牌进行一些自定义验证（例如使用 LDAP 或类似的东西验证目录服务），您可以编写自己的自定义 UsernameTokenValidator 覆盖 verifyPlaintextPassword(UsernameToken usernameToken) UsernameTokenValidator 并将其连接起来到你的 WSS4JInInterceptor 添加以下到你的 bean 定义

<property name="wssConfig">
        <ref bean="usernameTokenWssConfig"/>
</property>

并将引用的 class 添加到您的代码库：

@Component("usernameTokenWssConfig")
public class usernameTokenWssConfigWSSConfig {
    public usernameTokenWssConfig() {
        setValidator(WSSecurityEngine.USERNAME_TOKEN, new CustomUsernameTokenValidator());
        setRequiredPasswordType(WSConstants.PASSWORD_TEXT);
    }
}

如何增强回调处理程序 CXF 拦截器方法

How To enhance The Callback handler CXF Interceptor method

java

authentication

spring

cxf

interceptor