如何获取此内容中的所有 ipv4 地址

Question

谁能告诉我如何在 bash in linux 的内容中获取所有 ipv4 地址（在“（）”中）？

traceroute to 223.5.5.5 (223.5.5.5), 30 hops max, 60 byte packets
 1  1.2-88-23.rdns.scalabledns.com (23.88.2.1)  0.388 ms  0.404 ms  0.415 ms
 2  dist01-dc03-core.dc08.lax.ip4.scalabledns.com (172.246.0.235)  0.273 ms   18.825 ms  0.247 ms
 3  207.254.184.97 (207.254.184.97)  0.660 ms  0.771 ms  0.834 ms
 4  199.102.95.6 (199.102.95.6)  0.836 ms  0.808 ms  0.782 ms
 5  219.158.30.53 (219.158.30.53)  192.201 ms  192.186 ms  192.160 ms
 6  219.158.97.17 (219.158.97.17)  168.116 ms  168.193 ms  168.153 ms
 ....

结果应该是这样的

223.5.5.5
23.88.2.1
172.246.0.235
....

非常感谢您的帮助！

Answer 1

此 grep 行适用于您的示例：

grep -Po '.*\(\K[^)]*' file

它输出：

223.5.5.5
23.88.2.1
172.246.0.235
207.254.184.97
199.102.95.6
219.158.30.53
219.158.97.17

Answer 2

grep 与 PCRE (-P):

grep -Po '\(\K[^)]+(?=\))' file.txt

示例：

$ cat file.txt
traceroute to 223.5.5.5 (223.5.5.5), 30 hops max, 60 byte packets
 1  1.2-88-23.rdns.scalabledns.com (23.88.2.1)  0.388 ms  0.404 ms  0.415 ms
 2  dist01-dc03-core.dc08.lax.ip4.scalabledns.com (172.246.0.235)  0.273 ms   18.825 ms  0.247 ms
 3  207.254.184.97 (207.254.184.97)  0.660 ms  0.771 ms  0.834 ms
 4  199.102.95.6 (199.102.95.6)  0.836 ms  0.808 ms  0.782 ms
 5  219.158.30.53 (219.158.30.53)  192.201 ms  192.186 ms  192.160 ms
 6  219.158.97.17 (219.158.97.17)  168.116 ms  168.193 ms  168.153 ms

$ grep -Po '\(\K[^)]+(?=\))' file.txt
223.5.5.5
23.88.2.1
172.246.0.235
207.254.184.97
199.102.95.6
219.158.30.53
219.158.97.17

Answer 3

$ sed 's/.*(\([^)]*\).*//' file
223.5.5.5
23.88.2.1
172.246.0.235
207.254.184.97
199.102.95.6
219.158.30.53
219.158.97.17

Answer 4

bash中的一行脚本（bash中的基本知识就足够了） http://www.tldp.org/LDP/abs/html/string-manipulation.html

# while read l;do expr "$l" : ".*(\(.*\))";done <your_trc_file
223.5.5.5
23.88.2.1
172.246.0.235
207.254.184.97
199.102.95.6
219.158.30.53
219.158.97.17

更多说明：

# while read l;do echo "$l";done <file   ## read lines from a file

# # Matching with reg-exp by 'exp :' command
# expr "abcXdefghXXijk" : ".*X.*XX"      ## return length
11

# expr "abcXdefghXXijk" : ".*X\(.*\)XX"  ## return  extract 
defgh

如何获取此内容中的所有 ipv4 地址

how to get all the ipv4 address in this content

linux

bash

awk

grep

ipv4