在 AngularJS 中发送带有其他字段的 FormData

Send FormData with other field in AngularJS

我有一个包含两个 input text 和一个 upload 的表格。我必须将它发送到服务器,但我在将文件与文本连接时遇到了一些问题。服务器期望这个答案:

"title=first_input" "text=second_input" "file=my_file.pdf"

这是html:

<input type="text" ng-model="title">
<input type="text" ng-model="text">
<input type="file" file-model="myFile"/>
<button ng-click="send()">

这是控制器:

$scope.title = null;
$scope.text = null;

$scope.send = function(){
  var file = $scope.myFile;
  var uploadUrl = 'my_url';
  blockUI.start();
  Add.uploadFileToUrl(file, $scope.newPost.title, $scope.newPost.text, uploadUrl);
};

这是指令文件模型:

  return {
restrict: 'A',
link: function(scope, element, attrs) {
  var model = $parse(attrs.fileModel);
  var modelSetter = model.assign;

  element.bind('change', function(){
    scope.$apply(function(){
      modelSetter(scope, element[0].files[0]);
    });
  });
}
};

这是调用服务器的服务

  this.uploadFileToUrl = function(file, title, text, uploadUrl){
   var fd = new FormData();
   fd.append('file', file);
   var obj = {
     title: title,
     text: text,
     file: fd
   };
   var newObj = JSON.stringify(obj);

     $http.post(uploadUrl, newObj, {
       transformRequest: angular.identity,
       headers: {'Content-Type': 'multipart/form-data'}
     })
  .success(function(){
    blockUI.stop();
  })
  .error(function(error){
    toaster.pop('error', 'Errore', error);
  });
}

如果我尝试发送,我收到错误 400,响应为:Multipart form parse error - Invalid boundary in multipart: None。 请求的有效载荷是:{"title":"sadf","text":"sdfsadf","file":{}}

您正在将 JSON 格式的数据发送到不需要该格式的服务器。您已经提供了服务器需要的格式,因此您需要自己对其进行格式化,这非常简单。

var data = '"title='+title+'" "text='+text+'" "file='+file+'"';
$http.post(uploadUrl, data)

这永远行不通,您不能将 FormData 对象字符串化。

你应该这样做:

this.uploadFileToUrl = function(file, title, text, uploadUrl){
   var fd = new FormData();
   fd.append('title', title);
   fd.append('text', text);
   fd.append('file', file);

     $http.post(uploadUrl, obj, {
       transformRequest: angular.identity,
       headers: {'Content-Type': undefined}
     })
  .success(function(){
    blockUI.stop();
  })
  .error(function(error){
    toaster.pop('error', 'Errore', error);
  });
}

不要使用 POSTing 序列化 FormData 到服务器。这样做:

this.uploadFileToUrl = function(file, title, text, uploadUrl){
    var payload = new FormData();

    payload.append("title", title);
    payload.append('text', text);
    payload.append('file', file);

    return $http({
        url: uploadUrl,
        method: 'POST',
        data: payload,
        //assign content-type as undefined, the browser
        //will assign the correct boundary for us
        headers: { 'Content-Type': undefined},
        //prevents serializing payload.  don't do it.
        transformRequest: angular.identity
    });
}

然后使用:

MyService.uploadFileToUrl(file, title, text, uploadUrl).then(successCallback).catch(errorCallback);

在 AngularJS 中使用 $resource 你可以:

task.service.js

$ngTask.factory("$taskService", [
    "$resource",
    function ($resource) {
        var taskModelUrl = 'api/task/';
        return {
            rest: {
                taskUpload: $resource(taskModelUrl, {
                    id: '@id'
                }, {
                    save: {
                        method: "POST",
                        isArray: false,
                        headers: {"Content-Type": undefined},
                        transformRequest: angular.identity
                    }
                })
            }
        };
    }
]);

然后在模块中使用它:

task.module.js

$ngModelTask.controller("taskController", [
    "$scope",
    "$taskService",
    function (
        $scope,
        $taskService,
    ) {
    $scope.saveTask = function (name, file) {
        var newTask,
            payload = new FormData();
        payload.append("name", name);
        payload.append("file", file);
        newTask = $taskService.rest.taskUpload.save(payload);
        // check if exists
    }
}

这是完整的解决方案

html code,

创建文本 anf 文件上传字段,如下所示

    <div class="form-group">
        <div>
            <label for="usr">User Name:</label>
            <input type="text" id="usr" ng-model="model.username">
        </div>
        <div>
            <label for="pwd">Password:</label>
            <input type="password" id="pwd" ng-model="model.password">
        </div><hr>
        <div>
            <div class="col-lg-6">
                <input type="file" file-model="model.somefile"/>
            </div>


        </div>
        <div>
            <label for="dob">Dob:</label>
            <input type="date" id="dob" ng-model="model.dob">
        </div>
        <div>
            <label for="email">Email:</label>
            <input type="email"id="email" ng-model="model.email">
        </div>


        <button type="submit" ng-click="saveData(model)" >Submit</button>

directive code

创建一个文件模型指令来解析文件

.directive('fileModel', ['$parse', function ($parse) {
return {
    restrict: 'A',
    link: function(scope, element, attrs) {
        var model = $parse(attrs.fileModel);
        var modelSetter = model.assign;

        element.bind('change', function(){
            scope.$apply(function(){
                modelSetter(scope, element[0].files[0]);
            });
        });
    }
};}]);

Service code

附加文件和字段以形成数据并执行 $http.post 如下所示 记得保留 'Content-Type': undefined

 .service('fileUploadService', ['$http', function ($http) {
    this.uploadFileToUrl = function(file, username, password, dob, email, uploadUrl){
        var myFormData = new FormData();

        myFormData.append('file', file);
        myFormData.append('username', username);
        myFormData.append('password', password);
        myFormData.append('dob', dob);
        myFormData.append('email', email);


        $http.post(uploadUrl, myFormData, {
            transformRequest: angular.identity,
            headers: {'Content-Type': undefined}
        })
            .success(function(){

            })
            .error(function(){
            });
    }
}]);

In controller

现在在控制器中通过发送附加在参数中的所需数据来调用服务,

$scope.saveData  = function(model){
    var file = model.myFile;
    var uploadUrl = "/api/createUsers";
    fileUpload.uploadFileToUrl(file, model.username, model.password, model.dob, model.email, uploadUrl);
};

假设我们想要使用 POST 方法从 PHP 服务器获取特定图像的列表。

您必须在表单中为 POST 方法提供两个参数。这是你要怎么做。

app.controller('gallery-item', function ($scope, $http) {

    var url = 'service.php'; 

    var data = new FormData();

    data.append("function", 'getImageList');
    data.append('dir', 'all');

    $http.post(url, data, {
        transformRequest: angular.identity,
        headers: {'Content-Type': undefined}
      }).then(function (response) {

          // This function handles success
        console.log('angular:', response);

    }, function (response) {

        // this function handles error

    });
});

我已经在我的系统上测试过它并且可以正常工作。