在 Canvas 上画平滑的线条
Draw smooth Lines on a Canvas
我想用
在canvas上画一条线
context.globalCompositeOperation = 'destination-out';
context.globalAlpha = 0.118;
结果如下所示:
如果图像是黄色矩形,则为背景。我用一个圆圈将其拖放到图像上,它会绘制线条。如您所见,我画的线不是那么流畅。您可以看到圆圈,但没有复合线。
我创建了一个 JSFiddle here:
console.clear();
var history = new Array();
var imageObj = new Image();
var img = null;
stage = new Konva.Stage({
container: 'container',
width: 600,
height: 400
});
layer = new Konva.Layer();
stage.add(layer);
var rect = new Konva.Rect({
x: 30,
y: 30,
width: 438,
height: 300,
fill: 'yellow'
});
layer.add(rect);
var canvas = document.createElement('canvas');
var context = canvas.getContext('2d');
var circle = new Konva.Circle({
x: 0,
y: 0,
radius: 40,
opacity: 0.7,
fill: '#ff5e0a',
stroke: '#d95009',
strokeWidth: 1,
draggable: true
});
layer.add(circle);
circle.on('dragmove touchmove', function (e) {
erase(e.evt.clientX, e.evt.clientY, circle.radius(), img.x(), img.y());
});
imageObj.onload = function () {
canvas.width = imageObj.width;
canvas.height = imageObj.height;
context.drawImage(imageObj, 0, 0, imageObj.width, imageObj.height);
img = new Konva.Image({
x: 30,
y: 30,
image: canvas
});
layer.add(img);
circle.moveToTop();
layer.draw();
};
imageObj.crossOrigin = "anonymous";
imageObj.src = "https://dl.dropboxusercontent.com/u/47067729/darth-vader.jpg";
function erase(absX, absY, radius, imgX, imgY) {
var x = 0;
var y = 0;
// set pointer
circle.x(absX);
circle.y(absY);
x= absX - imgX;
y= absY - imgY;
context.globalCompositeOperation = 'destination-out';
context.globalAlpha = 0.118;
context.beginPath();
context.arc(x, y, radius, 0, 2 * Math.PI);
context.fill();
layer.draw();
}
如何在看不到每个小圆圈的地方绘制更平滑的复合线?
假设您的 Konva thingie 没有提供现成的解决方案,您将不得不以恒定位移插入触摸屏事件位置。
像这样:
circle.on('dragmove touchmove', function (e) {
if (circle.prev_pos) {
var dx = e.evt.clientX - circle.prev_pos.x;
var dy = e.evt.clientY - circle.prev_pos.y;
var dist = Math.max (Math.abs(dx), Math.abs(dy));
dx = dx / dist;
dy = dy / dist;
var x = circle.prev_pos.x;
var y = circle.prev_pos.y;
var d;
for (d = 0 ; d < dist ; d++)
{
erase(x, y, circle.radius(), img.x(), img.y());
x += dx;
y += dy;
}
}
circle.prev_pos = { x:e.evt.clientX, y:e.evt.clientY};
});
参见this fiddle。
我想用
在canvas上画一条线context.globalCompositeOperation = 'destination-out';
context.globalAlpha = 0.118;
结果如下所示:
如果图像是黄色矩形,则为背景。我用一个圆圈将其拖放到图像上,它会绘制线条。如您所见,我画的线不是那么流畅。您可以看到圆圈,但没有复合线。
我创建了一个 JSFiddle here:
console.clear();
var history = new Array();
var imageObj = new Image();
var img = null;
stage = new Konva.Stage({
container: 'container',
width: 600,
height: 400
});
layer = new Konva.Layer();
stage.add(layer);
var rect = new Konva.Rect({
x: 30,
y: 30,
width: 438,
height: 300,
fill: 'yellow'
});
layer.add(rect);
var canvas = document.createElement('canvas');
var context = canvas.getContext('2d');
var circle = new Konva.Circle({
x: 0,
y: 0,
radius: 40,
opacity: 0.7,
fill: '#ff5e0a',
stroke: '#d95009',
strokeWidth: 1,
draggable: true
});
layer.add(circle);
circle.on('dragmove touchmove', function (e) {
erase(e.evt.clientX, e.evt.clientY, circle.radius(), img.x(), img.y());
});
imageObj.onload = function () {
canvas.width = imageObj.width;
canvas.height = imageObj.height;
context.drawImage(imageObj, 0, 0, imageObj.width, imageObj.height);
img = new Konva.Image({
x: 30,
y: 30,
image: canvas
});
layer.add(img);
circle.moveToTop();
layer.draw();
};
imageObj.crossOrigin = "anonymous";
imageObj.src = "https://dl.dropboxusercontent.com/u/47067729/darth-vader.jpg";
function erase(absX, absY, radius, imgX, imgY) {
var x = 0;
var y = 0;
// set pointer
circle.x(absX);
circle.y(absY);
x= absX - imgX;
y= absY - imgY;
context.globalCompositeOperation = 'destination-out';
context.globalAlpha = 0.118;
context.beginPath();
context.arc(x, y, radius, 0, 2 * Math.PI);
context.fill();
layer.draw();
}
如何在看不到每个小圆圈的地方绘制更平滑的复合线?
假设您的 Konva thingie 没有提供现成的解决方案,您将不得不以恒定位移插入触摸屏事件位置。
像这样:
circle.on('dragmove touchmove', function (e) {
if (circle.prev_pos) {
var dx = e.evt.clientX - circle.prev_pos.x;
var dy = e.evt.clientY - circle.prev_pos.y;
var dist = Math.max (Math.abs(dx), Math.abs(dy));
dx = dx / dist;
dy = dy / dist;
var x = circle.prev_pos.x;
var y = circle.prev_pos.y;
var d;
for (d = 0 ; d < dist ; d++)
{
erase(x, y, circle.radius(), img.x(), img.y());
x += dx;
y += dy;
}
}
circle.prev_pos = { x:e.evt.clientX, y:e.evt.clientY};
});
参见this fiddle。