准备继续查看控制器时出现致命错误
fatal error when prepared to segue to view controller
我目前在 destViewController.titleLabel.text = "Testing Segue".
解包可选值 时遇到 意外发现 nil 的致命错误
我该如何修复它,因为它在转到 SecondViewController 时出现错误?如何避免在 titleLabel.text?
处得到 nil
class ViewController: UIViewController {
@IBAction func action(sender: AnyObject) {
let alertController: UIAlertController = UIAlertController (title: "Next Page", message: "", preferredStyle: .Alert)
let yesAction = UIAlertAction (title: "YES", style: .Default ) { action -> Void in self.performSegueWithIdentifier("test", sender: self)
}
alertController.addAction (yesAction)
self.presentViewController(alertController, animated: true, completion: nil)
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if (segue.identifier == "test") {
let destViewController : SecondViewController = segue.destinationViewController as SecondViewController
destViewController.titleLabel.text = "Testing Segue"
}
}
}
首先像这样更新 ViewController
中的代码:
class ViewController: UIViewController {
@IBAction func action(sender: AnyObject) {
let alertController: UIAlertController = UIAlertController (title: "Next Page", message: "", preferredStyle: .Alert)
let yesAction = UIAlertAction (title: "YES", style: .Default ) { action -> Void in self.performSegueWithIdentifier("test", sender: self)
}
alertController.addAction (yesAction)
self.presentViewController(alertController, animated: true, completion: nil)
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if (segue.identifier == "test") {
let destViewController : SecondViewController = segue.destinationViewController as SecondViewController
destViewController.textlbl = "Testing Segue"
}
}
}
在那之后我认为你不能用你的方式给 textLabel 赋值,所以在你的 SecondViewController
:
中用这种方式给那个标签赋值
import UIKit
class SecondViewController: UIViewController {
@IBOutlet weak var titleLabel: UILabel!
var textlbl = String()
override func viewDidLoad() {
super.viewDidLoad()
self.titleLabel.text = textlbl
}
}
并且HERE我创建了一个示例项目供您参考。
我目前在 destViewController.titleLabel.text = "Testing Segue".
解包可选值 时遇到 意外发现 nil 的致命错误我该如何修复它,因为它在转到 SecondViewController 时出现错误?如何避免在 titleLabel.text?
处得到 nilclass ViewController: UIViewController {
@IBAction func action(sender: AnyObject) {
let alertController: UIAlertController = UIAlertController (title: "Next Page", message: "", preferredStyle: .Alert)
let yesAction = UIAlertAction (title: "YES", style: .Default ) { action -> Void in self.performSegueWithIdentifier("test", sender: self)
}
alertController.addAction (yesAction)
self.presentViewController(alertController, animated: true, completion: nil)
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if (segue.identifier == "test") {
let destViewController : SecondViewController = segue.destinationViewController as SecondViewController
destViewController.titleLabel.text = "Testing Segue"
}
}
}
首先像这样更新 ViewController
中的代码:
class ViewController: UIViewController {
@IBAction func action(sender: AnyObject) {
let alertController: UIAlertController = UIAlertController (title: "Next Page", message: "", preferredStyle: .Alert)
let yesAction = UIAlertAction (title: "YES", style: .Default ) { action -> Void in self.performSegueWithIdentifier("test", sender: self)
}
alertController.addAction (yesAction)
self.presentViewController(alertController, animated: true, completion: nil)
}
override func prepareForSegue(segue: UIStoryboardSegue, sender: AnyObject?) {
if (segue.identifier == "test") {
let destViewController : SecondViewController = segue.destinationViewController as SecondViewController
destViewController.textlbl = "Testing Segue"
}
}
}
在那之后我认为你不能用你的方式给 textLabel 赋值,所以在你的 SecondViewController
:
import UIKit
class SecondViewController: UIViewController {
@IBOutlet weak var titleLabel: UILabel!
var textlbl = String()
override func viewDidLoad() {
super.viewDidLoad()
self.titleLabel.text = textlbl
}
}
并且HERE我创建了一个示例项目供您参考。