为什么 public static void main(String args[]) 错误并且它说表达式的非法开始?
why the public static void main(String args[]) error and it say illegal start of expression?
我是 netbeans 的新手,正在做功课
我正在尝试连接到 derby 数据库,但是 public static void 显示错误我不知道该怎么做这是我的代码:
导入 java.sql.;
导入 javax.swing.;
public class addcriminal 扩展 javax.swing.JFrame {
public addcriminal() {
initComponents();
}
@SuppressWarnings("unchecked")
private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {
try{
String url="jdbc:derby://localhost:1527/criminal records ";
String username ="naim";
String password = "12345";
Connection con = DriverManager.getConnection(url,username,password);
Statement stmt = con.createStatement ();
String Query;
Query = "INSERT INTO CRIMINAL RECORDS (ID, NAME, AGE, ICNO, SEX, CRIME, PERIODS)VALUES ('"+txtno.getText()+"' , '"+txtname.getText()+"', '"+txtage.getText()+"', '"+txtic.getText()+"','"+txtic.getText()+"', '"+combosex.getSelectedItem()+"', '"+txtcrime.getText()+"', '"+txtperiods.getText()+"')";
stmt.execute(Query);
JOptionPane.showMessageDialog(null, "criminal recorded");
txtno.setText(null);
txtname.setText(null);
txtage.setText(null);
txtic.setText(null);
combosex.setSelectedItem(null);
txtcrime.setText(null);
txtperiods.setText(null);
}
catch(SQLException ex) {
JOptionPane.showMessageDialog(null, ex.toString());
}
public static void main(String args[]) { <<ERROR HERE
java.awt.EventQueue.invokeLater(new Runnable() {
public void run() {
new addcriminal().setVisible(true);
}
});
}
在我看来,您似乎忘记了 catch 语句中的右大括号。
catch(SQLException ex) {
JOptionPane.showMessageDialog(null, ex.toString());
}
我是 netbeans 的新手,正在做功课 我正在尝试连接到 derby 数据库,但是 public static void 显示错误我不知道该怎么做这是我的代码: 导入 java.sql.; 导入 javax.swing.;
public class addcriminal 扩展 javax.swing.JFrame {
public addcriminal() {
initComponents();
}
@SuppressWarnings("unchecked")
private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {
try{
String url="jdbc:derby://localhost:1527/criminal records ";
String username ="naim";
String password = "12345";
Connection con = DriverManager.getConnection(url,username,password);
Statement stmt = con.createStatement ();
String Query;
Query = "INSERT INTO CRIMINAL RECORDS (ID, NAME, AGE, ICNO, SEX, CRIME, PERIODS)VALUES ('"+txtno.getText()+"' , '"+txtname.getText()+"', '"+txtage.getText()+"', '"+txtic.getText()+"','"+txtic.getText()+"', '"+combosex.getSelectedItem()+"', '"+txtcrime.getText()+"', '"+txtperiods.getText()+"')";
stmt.execute(Query);
JOptionPane.showMessageDialog(null, "criminal recorded");
txtno.setText(null);
txtname.setText(null);
txtage.setText(null);
txtic.setText(null);
combosex.setSelectedItem(null);
txtcrime.setText(null);
txtperiods.setText(null);
}
catch(SQLException ex) {
JOptionPane.showMessageDialog(null, ex.toString());
}
public static void main(String args[]) { <<ERROR HERE
java.awt.EventQueue.invokeLater(new Runnable() {
public void run() {
new addcriminal().setVisible(true);
}
});
}
在我看来,您似乎忘记了 catch 语句中的右大括号。
catch(SQLException ex) {
JOptionPane.showMessageDialog(null, ex.toString());
}