访问 python 个对象的名称

Question

我制作了一个 class 来使用电热丝：

class Heating_wire:

    def __init__(self, ro, L,d,alpha):

        self.ro = ro
        self.L = L
        self.d = d
        self.alpha = alpha
        self.RT = [1]
        self.vector_T = [1]
    def get_R20(self):
        self.R_20 =  self.ro*self.L/(np.pi*(self.d/2)**2)

    def  calcular_RT(self,vector_temp):
        self.vector_T = vector_temp
        self.RT =  [self.R_20*(1 + temp*self.alpha) for temp in vector_temp ]
        return self.RT

实例化一些对象：

kantal = Heating_wire(1.45,0.25,0.3,4e-5)
nicromo = Heating_wire(1.18,0.25,0.3,0.0004)
ferroniquel = Heating_wire(0.86,0.25,0.3,9.3e-4)

wires = [kantal,nicromo,ferroniquel]

并做了一个情节：

leg = []
vector_temp = np.linspace(20,1000,1000)
for wire in sorted(wires):
    wire.get_R20()
    wire.get_RT(vector_temp)
    line, = plt.plot(wire.vector_T,wire.RT)
    leg.append(line)
plt.legend(leg,sorted(wires))

问题是我在图例中没有得到正确的名称，而是对对象的引用：

如果我添加名称属性

def __init__(self,name, ro, L,d,alpha):
    self.name = name

我可以追加名字

leg = []

names= []
vector_temp = np.linspace(20,1000,1000)
for wire in sorted(wires):
    wire.get_R20()
    wire.get_RT(vector_temp)
    line, = plt.plot(wire.vector_T,wire.RT)
    leg.append(line)
    names.append(wire.name)
plt.legend(leg,names,loc='best')

但我想知道是否有更简单的方法可以直接使用电线列表中的对象名称来解决此问题：

kantal = Heating_wire(1.45,0.25,0.3,4e-5)
nicromo = Heating_wire(1.18,0.25,0.3,0.0004)
ferroniquel = Heating_wire(0.86,0.25,0.3,9.3e-4)

wires = [kantal,nicromo,ferroniquel]

Answer 1

就这样做，没有重复:

wires = [
    Heating_wire("kantal", 1.45,0.25,0.3,4e-5),
    Heating_wire("nicromo", 1.18,0.25,0.3,0.0004),
    Heating_wire("ferroniquel", 0.86,0.25,0.3,9.3e-4)
]

要回答你的问题，不，对象无法访问它们被赋予的名称。

访问 python 个对象的名称

Access name of python objects

python

oop

names