QML 堆栈视图 Status.Inactive

Question

QML StackView Status.Inactivestatus 是否意味着当视图进入此状态时，它的可见性隐式设置为 false？因此，出于性能原因，我不需要将视图的可见性显式设置为 false？

Answer 1

您可以通过将以下内容添加到 StackView 中的项目来验证：

onVisibleChanged: print(visible)

看code，好像确实是隐藏的：

/*! \internal */
function animationFinished()
{
    if (!__currentTransition || __currentTransition.animation.running)
        return

    __currentTransition.animation.runningChanged.disconnect(animationFinished)
    __currentTransition.exitItem.visible = false
    __setStatus(__currentTransition.exitItem, Stack.Inactive);
    __setStatus(__currentTransition.enterItem, Stack.Active);
    __currentTransition.properties.animation = __currentTransition.animation
    root.delegate.transitionFinished(__currentTransition.properties)

    if (!__currentTransition.push || __currentTransition.replace)
        __cleanup(__currentTransition.outElement)

    __currentTransition = null
}

QML 堆栈视图 Status.Inactive

QML StackView Status.Inactive

qml

stackview

qt5