PDO+PHP+SQLITE+PRINT+'ME' = Table 结果不正确不是预期的

Question

我试图用 pdo 创建 sqlite 数据库并在 table 中回显它有点工作，但它有一些问题，我想你们可能知道它

这是我的 php 代码

<?php
    try
    {
    $db = new PDO('sqlite:randvalue.sqlite');
    $db->exec("CREATE TABLE company (revenue_value INTEGER PRIMARY KEY, month VARCHAR)");

    $start = 2000;
    $end = 2000 * 1.2;
    $numbers = array($start);

    for($i=0; $i<10; $i++) {
    $numbers[] = rand($start, $end);
    $db->exec("INSERT INTO company(revenue_value) VALUES ('2000')");
    }
    $numbers[] = $end;

    $stmt = $db->prepare('INSERT INTO company (revenue_value) VALUES (?)');
    foreach($numbers as $number) {
    $stmt->execute(array($number));
    }

    $months = array("Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec");
    $stmt = $db->prepare('INSERT INTO company (month) VALUES (?)'); 
    foreach ($months as $month) {
    $stmt->execute(array($month));
    }

    print "<table border=1>";
    print "<tr><td>value</td>";
    print "<td>month</td></tr>";
    $result = $db->query('SELECT * FROM company');

    foreach($result as $row)
    {
        print "<tr><td>".$row['revenue_value']."</td>";
        print "<td>".$row['month']."</td></tr>";
    }
    print "</table>";

    $db = NULL;

    }

    catch(PDOException $e)
    {
        print 'Exception : '.$e->getMessage();
    }

    ?>

结果

我认为问题是数字 rand 和月份数组没有同时执行，因此创建了 table。有没有办法让他们写在同一栏

Answer 1

删除插入的exec版本：

// remove this line
$db->exec("INSERT INTO company(revenue_value) VALUES ('2000')");

使用单个插入：

try
{
    $db = new PDO('sqlite:randvalue.sqlite');
    $db->exec("CREATE TABLE company (revenue_value INTEGER PRIMARY KEY, month VARCHAR)");

    $start = 2000;
    $end = 2000 * 1.2;
    $numbers = array($start);

    for($i=0; $i<10; $i++) {
        $numbers[] = rand($start, $end);
    }
    $numbers[] = $end;

    $months = array("Jan", "Feb", "Mar", "Apr", "May", "Jun", "Jul", "Aug", "Sep", "Oct", "Nov", "Dec");
    $stmt = $db->prepare('INSERT INTO company (revenue_value, month) VALUES (?, ?)');
    for($j = 0, $count = count($numbers); $j < $count; $j++) {
        $stmt->execute(array($numbers[$j], $months[$j]));
    }
    // then continue on to output the table

PDO+PHP+SQLITE+PRINT+'ME' = Table 结果不正确不是预期的

PDO+PHP+SQLITE+PRINT+'ME' = Table result incorrect not what expecting

php

sqlite

pdo