多个嵌入形式的 symfony 2 错误

Question

我在使用 symfony2 的多重嵌入表单上遇到一个奇怪的错误。

这是我的结构：

被许可人 <- OneToMany -> 注册 <- OneToMany -> 付款

被许可方:

/**
 * @ORM\OneToMany(targetEntity="cM\ManagementBundle\Entity\Registration", mappedBy="licensee", cascade={"persist" })
 */
private $registrations;

public function __construct()
{
    $this->registrations = new ArrayCollection();
}

public function addRegistration(\cM\ManagementBundle\Entity\Registration $registration)
{
    $this->registrations[] = $registration;
    $registration->setLicensee($this);

    return $this;
}

public function removeRegistration(\cM\ManagementBundle\Entity\Registration $registration)
{
    $this->registrations->removeElement($registration);
}

public function setRegistrations(ArrayCollection $registrations)
{
    foreach ($registrations as $registration) {
        $registration->addLicensee($this);
    }

    $this->registrations = $registrations;
}

public function getRegistrations() {
    return $this->registrations;
}

报名:

/**
 * @ORM\ManyToOne(targetEntity="cM\ManagementBundle\Entity\Licensee", inversedBy="registrations")
 * @ORM\JoinColumn(nullable=false)
 */
private $licensee;

/**
 * @ORM\OneToMany(targetEntity="cM\ManagementBundle\Entity\Payment", mappedBy="registration", cascade={"ALL"}, orphanRemoval=true)
 * @ORM\JoinColumn(nullable=false)
 */
private $payments;

public function __construct() {
    $this->payments = new ArrayCollection();
}

/**
 * Set licensee
 *
 * @param \cM\ManagementBundle\Entity\Licensee $licensee
 * @return Registration
 */
public function setLicensee(\cM\ManagementBundle\Entity\Licensee $licensee)
{
    $this->licensee = $licensee;

    return $this;
}

/**
 * Get licensee
 *
 * @return \cM\ManagementBundle\Entity\Licensee 
 */
public function getLicensee()
{
    return $this->licensee;
}

/**
 * Add payments
 *
 * @param \cM\ManagementBundle\Entity\Payment $payment
 * @return Registration
 */
public function addPayment(\cM\ManagementBundle\Entity\Payment $payment)
{
    $payment->setRegistration($this);
    $this->payments[] = $payment;

    return $this;
}

/**
 * Remove payments
 *
 * @param \cM\ManagementBundle\Entity\Payment $payment
 */
public function removePayment(\cM\ManagementBundle\Entity\Payment $payment)
{
    $this->payments->removeElement($payment);
}

/**
 * Get payments
 *
 * @return \Doctrine\Common\Collections\Collection 
 */
public function getPayments()
{
    return $this->payments;
}

付款:

/**
 * @ORM\ManyToOne(targetEntity="cM\ManagementBundle\Entity\Registration", inversedBy="payments")
 * @ORM\JoinColumn(nullable=false, onDelete="CASCADE")
 */
private $registration;

/**
 * Set registration
 *
 * @param \cM\ManagementBundle\Entity\Registration $registration
 * @return Payment
 */
public function setRegistration(\cM\ManagementBundle\Entity\Registration $registration)
{
    $this->registration = $registration;

    return $this;
}

/**
 * Get registration
 *
 * @return \cM\ManagementBundle\Entity\Registration 
 */
public function getRegistration()
{
    return $this->registration;
}

被许可人类型:

$builder
        ->add('registrations', 'collection', array(
            'type'         => new RegistrationType(),
            'allow_add'    => true,
            'by_reference' => false,
        ))

注册类型:

$builder
        ->add('payments', 'collection', array(
            'type'         => new PaymentType(),
            'allow_add'    => true,
            'allow_delete' => true,
            'by_reference' => false,
            'required'     => false,
        ))

支付类型:

$builder
        ->add('amount', 'text')

我的主控制器：LicenseeController

$form = $this->createForm('cm_managementbundle_licensee', $licensee);
$form->handleRequest($this->getRequest());

if ($this->getRequest()->getMethod() === 'POST') {
    if ($form->isValid()) {
        $em = $this->getDoctrine()->getManager();
        $em->persist($licensee);

        $em->flush();

        return $this->redirect($this->generateUrl('homepage'));
    }
}

在被许可方表格中，注册是强制性的，但付款是可选的。

当我使用注册信息创建新的被许可人并且没有付款时：没问题，信息很好地保存在数据库中
当我编辑被许可人并添加一些付款时：没问题
当我使用注册信息和使用一笔或多笔付款创建新的被许可人时，出现原则错误，指出注册不能为空：

使用参数 [null, null, ...] 执行 'INSERT INTO Registration (registrationDate, registrationNumber, ...) VALUES (?, ?, ...)' 时发生异常：

SQLSTATE[23000]：违反完整性约束：1048 列 'registrationDate' 不能为空

当我查看 symfony 分析器时，我看到该学说启动了 2 个注册查询 table :

- "START TRANSACTION"
- INSERT INTO Licensee (lastname, firstname, ...) VALUES (?, ?, ...)
Parameters: { 1: Simpson, 2: Homer, ... }
- INSERT INTO Registration (registrationDate, registrationNumber, ...) VALUES (?, ?, ...)
Parameters: { 1: '2015-01-29 00:00:00', 2: '1234', ... }
- INSERT INTO Registration (registrationDate, registrationNumber, ...) VALUES (?, ?, ...)
Parameters: { 1: null, 2: null, ... }

那为什么有第二个注册查询，所有参数都为空，而第一个是正确的？

我错过了什么？

感谢各位大王的帮助。

Answer 1

好的，成功解决了这个问题。

我必须更改 Payment Collection 的原型名称

->add('payments', 'collection', array(
    'type' => new PaymentType(),
    'allow_add' => true,
    'prototype_name' => 'payments_name'
))

所以当我在添加新付款时使用 javascript 动态更改名称时，我不会在此过程中更改父名称（注册）（默认情况下，所有原型集合都具有相同的名称（姓名)

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