根据前 2 列合并 2 个列表

Question

我需要根据第 1 列和第 2 列合并 2 个列表

文件 1:

client1,server1,3000.00
client1,server2,2500.00
client1,server3,1500.00
client2,server1,4500.00
client2,server2,2300.00
client2,server3,1230.00
client3,server1,3400.00
client3,server2,4500.00
client3,server3,1245.00
client4,server1,3400.00
client5,server2,4500.00
client6,server3,1245.00
client7,server1,3400.00
client7,server2,4500.00
client8,server3,1245.00
client8,server1,3400.00
client8,server2,4500.00
client9,server3,1245.00

文件 2:

client1,server1,windows,250g
client1,server2,linux,450g
client1,server3,linux,400g
client2,server1,windows,250g
client2,server2,linux,450g
client2,server3,linux,400g
client3,server1,windows,250g
client3,server2,linux,450g
client3,server3,linux,400g

我需要的是用 file1 的第 1 列和第 2 列中的缺失值更新 file2，并添加逗号以保持相同的列数

对于这个例子，输出应该是这样的：

client1,server1,windows,250g
client1,server2,linux,450g
client1,server3,linux,400g
client2,server1,windows,250g
client2,server2,linux,450g
client2,server3,linux,400g
client3,server1,windows,250g
client3,server2,linux,450g
client3,server3,linux,400g
client4,server1,,
client5,server2,,
client6,server3,,
client7,server1,,
client7,server2,,
client8,server3,,
client8,server1,,
client8,server2,,
client9,server3,,

我尝试过使用 awk 和 join，但无法获得相同的结果

如果创建新文件更容易，那就没问题

感谢您的帮助

Answer 1

试试这一行：

awk -F, '{k= FS }NR==FNR{a[k]++;print;next}!a[k]{print k",,"}' file2 file1

Answer 2

另一种 awk 方式

awk -F, -vOFS="," 'NR!=FNR{NF--;NF+=2}!a[ FS ]++' test2 test

或

awk -F, 'NR!=FNR{[=11=]= FS ",,"}!a[ FS ]++' test2 test

最短

awk -F, '{x=","}NR!=FNR{[=12=]=x",,"}!a[x]++' test2 test

Answer 3

使用join命令。问题是 join 不能连接多个字段，所以我们需要临时操作第一个逗号：

join -t , -o 0,2.2,2.3 -a 1 <(sed 's/,/:/' file1) <(sed 's/,/:/' file2) | sed 's/:/,/'

根据前 2 列合并 2 个列表

merge 2 lists based on first 2 columns

join

awk