使用两个外键关系时的 Hibernate 查询异常

Question

我正在开发 Spring-MVC 应用程序。在应用程序中，我正在研究聊天功能。您可以将聊天功能想象成类似于 facebook 风格。在这里，有两个用户之间的对话，当加载对话时，可以看到里面的文本。所以我有 3 个表，用户、对话、回复。因此 Conversation 与用户只有两个外键关系，即发送者和接收者。

每当有新消息到达时，都会将其添加到回复中，并与对话建立外键关系。这样，每当我需要加载对话时，我只需搜索两个用户 ID，然后从回复中加载它。

现在，当我尝试在数据库中搜索 conversationid 时，我正在使用查询来搜索它们，但出现错误。错误代码如下：

错误代码：

org.springframework.web.util.NestedServletException: Request processing failed; nested exception is org.hibernate.QueryException: could not resolve property: userinfo_id of: com.WirTauschen.model.User [from com.WirTauschen.model.Messages as m where m.sender.id=:senderid and m.receiver.userinfo_id=:receiverid]
    org.springframework.web.servlet.FrameworkServlet.processRequest(FrameworkServlet.java:973)
    org.springframework.web.servlet.FrameworkServlet.doGet(FrameworkServlet.java:852)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:620)
    org.springframework.web.servlet.FrameworkServlet.service(FrameworkServlet.java:837)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:727)
    org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)
    org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:88)
    org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:107)
    org.springframework.orm.hibernate4.support.OpenSessionInViewFilter.doFilterInternal(OpenSessionInViewFilter.java:152)
    org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:107)
    org.springframework.security.web.FilterChainProxy$VirtualFilterChain.doFilter(FilterChainProxy.java:330)

用户模型：

@Entity
@Table(name="userinfo")
public class User implements UserDetails{

@Id
@Column(name="id")
@GeneratedValue(strategy = GenerationType.SEQUENCE,generator = "user_seq_gen")
@SequenceGenerator(name ="user_seq_gen", sequenceName = "user_seq")
public int id;


 @OneToMany(mappedBy = "sender", fetch = FetchType.EAGER)
    private Set<Messages> messages1 = new HashSet<Messages>();

 @OneToMany(mappedBy = "receiver", fetch = FetchType.EAGER)
    private Set<Messages> messages2 = new HashSet<Messages>();

// getters 和 setters 省略 }

消息模型：

@Entity
@Table(name = "conversation")
public class Messages {
  @ManyToOne
    @JoinColumn(name = "id")
    private User sender;

  @ManyToOne
    @JoinColumn(name = "userinfo_id")
    private User receiver;

// Getters and setters ommitted

}

消息DAOImpl :

@Override
    public Long returnConversationId(int senderid, int receiverid) {
        session = this.sessionFactory.getCurrentSession();
        Query query1 = session.createQuery("from Messages as m where m.sender.id=:senderid and m.receiver.userinfo_id=:receiverid");
        query1.setParameter("senderid",senderid);
        query1.setParameter("receiverid",receiverid);
        List<Messages> firstDataList = query1.list();
        List<Messages> secondDataList = new ArrayList<Messages>();
        if(firstDataList.isEmpty()) {
            Query query2 = session.createQuery("from Messages as m where m.sender.id=:receiverid and m.receiver.userinfo_id=:senderid");
            query2.setParameter("senderid", senderid);
            query2.setParameter("receiverid", receiverid);
           secondDataList = query2.list();
        } else {
           for(Messages messages : firstDataList){
               return messages.getConversation_id();
           }
        }

        if(secondDataList.isEmpty()){
            return null;
        } else {
            for (Messages messages : secondDataList){
                return messages.getConversation_id();
            }
        }

        return null;
    }

SQL 代码：

CREATE TABLE userinfo
(
  id integer NOT NULL,
  email character varying,
  username character varying,
  password character varying,
  accountstatus boolean DEFAULT false,
  CONSTRAINT id PRIMARY KEY (id)
)

CREATE TABLE conversation
(
  conversation_id numeric NOT NULL,
  id integer NOT NULL,
  userinfo_id integer NOT NULL,
  lastmessage character varying,
  CONSTRAINT conversation_id PRIMARY KEY (conversation_id),
  CONSTRAINT userinfo_conversation_fk FOREIGN KEY (id)
      REFERENCES userinfo (id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE NO ACTION,
  CONSTRAINT userinfo_conversation_fk1 FOREIGN KEY (userinfo_id)
      REFERENCES userinfo (id) MATCH SIMPLE
      ON UPDATE NO ACTION ON DELETE NO ACTION
)

欢迎任何指点。请注意，数据库中有一列 userinfo_id。谢谢你。

Answer 1

你的模型 "userinfo_id" 在哪里 "User"，你应该有这样的东西：

@Id
@Column(name="id")
@GeneratedValue
private int id;

在您的消息模型中：

@Entity
@Table(name = "conversation")
public class Messages {
  @ManyToOne
    @JoinColumn(name = "id")
    private User sender;

  @ManyToOne
    @JoinColumn(name = "id")
    private User receiver;

// Getters and setters ommitted

}

使用两个外键关系时的 Hibernate 查询异常

Hibernate query exception when using two foreign key relations

hibernate

spring-mvc