Android权限请求代码问题

Question

如何申请权限？我尝试了文档，但常量 int 请求代码 MY_PERMISSIONS_REQUEST_CALL_PHONE 似乎不起作用，还有什么要记住的向后兼容性吗？

ActivityCompat.requestPermissions(getApplicationContext(),
                            new String[]{Manifest.permission.READ_CONTACTS},
                            MY_PERMISSIONS_REQUEST_CALL_PHONE);

如何声明MY_PERMISSIONS_REQUEST_CALL_PHONE常量int？

Answer 1

            if (ActivityCompat.checkSelfPermission(this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
                // TODO: Consider calling
                //    ActivityCompat#requestPermissions
                // here to request the missing permissions, and then overriding
                //   public void onRequestPermissionsResult(int requestCode, String[] permissions,
                //                                          int[] grantResults)
                // to handle the case where the user grants the permission. See the documentation
                // for ActivityCompat#requestPermissions for more details.
                return;
            }
Intent intent = new Intent(Intent.ACTION_CALL);
            intent.setData(Uri.parse("tel:" + "123456"));
            startActivity(intent);

尝试这样做。

Answer 2

试试下面的代码希望对你有帮助。首先，这将在允许它调用该号码后询问您是否允许弹出窗口。

if (ContextCompat.checkSelfPermission(HomePanelActivity.this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED) {
            if (ActivityCompat.shouldShowRequestPermissionRationale(HomePanelActivity.this,
                    Manifest.permission.CALL_PHONE)) {
                ActivityCompat.requestPermissions(HomePanelActivity.this, new String[]{Manifest.permission.CALL_PHONE}, REQUEST_PERMISSION);
            }
        } else {
            Intent callIntent = new Intent(Intent.ACTION_CALL);
            callIntent.setData(Uri.parse("tel:" + phoneNumber));
            if (ActivityCompat.checkSelfPermission(HomePanelActivity.this, Manifest.permission.CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {
                startActivity(callIntent);
            }
        }

@Override
    public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults) {
        switch (requestCode) {
            case 10:
                if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                    Intent callIntent = new Intent(Intent.ACTION_CALL);
                    callIntent.setData(Uri.parse("tel:" + phoneNumberToCall));
                    if (ActivityCompat.checkSelfPermission(HomePanelActivity.this, Manifest.permission.CALL_PHONE) == PackageManager.PERMISSION_GRANTED) {
                        startActivity(callIntent);
                    }
                } else {
                    Snackbar.make(drawerLayout, "You Deny permission", Snackbar.LENGTH_SHORT).show();
                return;
            }
        }
    };

Answer 3

对于较低的版本，您只需要在清单中声明权限，但是对于 marshmellow 你需要在代码中给出它，你想要执行代码的地方。

这里，你想打个电话。因此，insert/include 下面代码块中提供的代码用于进行调用。

   public void makeCall(){
       Intent intent = new Intent(Intent.ACTION_CALL);
       intent.setData(Uri.parse("tel:" + "123456"));
       int result = ContextCompat.checkSelfPermission(context, Manifest.permission.CALL_PHONE);
       if (result == PackageManager.PERMISSION_GRANTED){
           startActivity(intent);
       } else {
           requestForCallPermission(); 
       }
  }

  private void requestPermission(){
    if(ActivityCompat.shouldShowRequestPermissionRationale(activity,Manifest.permission.CALL_PHONE)){} 
    else {
           ActivityCompat.requestPermissions(activity,new String[]{Manifest.permission.CALL_PHONE},PERMISSION_REQUEST_CODE);
       }
  }

  @Override
  public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults) {
    switch (requestCode) {
        case PERMISSION_REQUEST_CODE:
            if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) { 
                makeCall(); 
            } 
            break;
      }
  }

Answer 4

public void makeCall(String s)
{
    Intent intent = new Intent(Intent.ACTION_CALL);
    intent.setData(Uri.parse("tel:" + s));
    if (ActivityCompat.checkSelfPermission(this, Manifest.permission.CALL_PHONE) != PackageManager.PERMISSION_GRANTED){

        requestForCallPermission();

    } else {
        startActivity(intent);

    }
}
public void requestForCallPermission()
{

    if (ActivityCompat.shouldShowRequestPermissionRationale(this,Manifest.permission.CALL_PHONE))
    {
    }
    else {

        ActivityCompat.requestPermissions(this,new String[]{Manifest.permission.CALL_PHONE},PERMISSION_REQUEST_CODE);
    }
}

@Override
public void onRequestPermissionsResult(int requestCode, String permissions[], int[] grantResults)
{
    switch (requestCode) {
        case PERMISSION_REQUEST_CODE:
            if (grantResults.length > 0 && grantResults[0] == PackageManager.PERMISSION_GRANTED) {
                makeCall("100");
            }
            break;
    }
}

//现在调用方法makeCall("your_desire_phone_numder"); 打电话（“100”）； Link for more details

Answer 5

您还需要在 AndroidManifest.xml 中指定要使用的权限喜欢

<uses-permission android:name="android.permission.READ_CONTACTS"></uses-permission>

Android权限请求代码问题

Android Permission Request Code Issue

android

android-permissions

phone-call