Django formset factory ChoiceField 导致 is_valid 失败和 return false

Question

我正在使用表单集工厂生成一组动态的表单元素。我想添加一组动态单选按钮和下拉菜单，但是当我使用 ChoiceField 时，search.is_valid() 的计算结果为 false。我确定我在做一些明显错误的事情，但我找不到它。

...
    search_formset = formset_factory(SearchForm, extra=num_extra_charts)

    # data to initialize forms
    data = {
        'form-TOTAL_FORMS': str(num_extra_charts),
        'form-INITIAL_FORMS': str(num_extra_charts),
        'form-MAX_NUM_FORMS': '',
    }
    self.search_forms = search_formset(get_request or data)
    if self.search_forms.is_valid():

...

class SearchForm(forms.Form):

    ORDERS = [('ASC', 'ASC'),
          ('DESC', 'DESC')]

    search = forms.CharField(label='',
                         max_length=250,
                         required=False,
                         widget=forms.TextInput(
                             attrs={'placeholder': 'ex. Matt Damon AND war'}),
                         )

    property = forms.CharField(label='',
                           max_length=250,
                           required=False,
                           widget=forms.TextInput(
                               attrs={'placeholder': 'Property Filter'}),
                           )

    limit = forms.CharField(label='',
                        max_length=250,
                        required=False,
                        widget=forms.TextInput(
                            attrs={'placeholder': 'Limit - Default: 25'}),
                        )

    orders = forms.CharField(widget=forms.Select(choices=ORDERS))

Answer 1

你有：

self.search_forms = search_formset(get_request or data)

这很不寻常。这意味着表单集总是绑定的。

通常你会

self.search_forms = search_formset(get_request or None)

由于您没有 required=False，这意味着您必须在表单数据中提供 orders 字段的值，否则您将收到错误消息。

Django formset factory ChoiceField 导致 is_valid 失败和 return false

Django formset factory ChoiceField causes is_valid to fail and return false

forms

django

formset

radio-button