bash 中数组的内联扩展

Question

我正在尝试扩展 bash 中的数组：

FILES=(2009q{1..4})
echo ${FILES[@]}
echo ${FILES[@]}.zip

输出为：

2009q1 2009q2 2009q3 2009q4
2009q1 2009q2 2009q3 2009q4.zip

但是我怎样才能像 echo 2009q{1..4}.zip 那样扩展最后一行，使最后一行看起来像：

2009q1.zip 2009q2.zip 2009q3.zip 2009q4.zip

...但使用数组 FILES?

Answer 1

您可以使用 printf:

printf "%s.zip " "${FILES[@]}"

2009q1.zip 2009q2.zip 2009q3.zip 2009q4.zip

Answer 2

FILES=(2009q{1..4})
echo ${FILES[@]/%/.zip}

输出：

2009q1.zip 2009q2.zip 2009q3.zip 2009q4.zip

来自 Bash 的 Parameter Expansion:

${parameter/pattern/string}: The pattern is expanded to produce a pattern just as in filename expansion. Parameter is expanded and the longest match of pattern against its value is replaced with string. If pattern begins with '/', all matches of pattern are replaced with string. Normally only the first match is replaced. If pattern begins with '#', it must match at the beginning of the expanded value of parameter. If pattern begins with '%', it must match at the end of the expanded value of parameter. If string is null, matches of pattern are deleted and the / following pattern may be omitted. If parameter is '@' or '', the substitution operation is applied to each positional parameter in turn, and the expansion is the resultant list. If parameter is an array variable subscripted with '@' or '', the substitution operation is applied to each member of the array in turn, and the expansion is the resultant list.

bash 中数组的内联扩展

Inline expansion of arrays in bash

arrays

bash

expansion