Mysql 计算系统停机记录的上一个结束时间和当前开始时间之间的分钟数

Question

我需要帮助，我需要计算当前事件的前一个结束日期和开始日期之间的分钟差, 根据系统排。

这是 table:

id |system |start |end | ------------------------------------------------------------ 2 | system 1 | 2016-01-01 12:00:00 | 2016-01-01 13:00:00 | ------------------------------------------------------------ 3 | system 1 | 2016-01-02 11:00:00 | 2016-01-02 12:00:00 | ------------------------------------------------------------ 5 | system 1 | 2016-01-03 15:00:00 | 2016-01-03 16:00:00 | ------------------------------------------------------------ 6 | system 2 | 2016-01-01 10:00:00 | 2016-01-01 11:00:00 | ------------------------------------------------------------ 7 | system 2 | 2016-01-02 17:00:00 | 2016-01-02 18:00:00 |

这是结果：

ID为2和6的两条系统记录没有'end date'的先行记录做减法：

id | system | diff_min | --------------------------------- 2 | system 1 | 0 | --------------------------------- 3 | system 1 | 1380 | --------------------------------- 5 | system 1 | 1620 | --------------------------------- 6 | system 2 | 0 | --------------------------------- 7 | system 2 | 1800 | ---------------------------------

Answer 1

您可以使用两个内置函数实现此目的

 select id, system, TIMESTAMPDIFF(MINUTE, endDate, startDate)  diff_min

或

 select id, system, TIMEDIFF(endDate, startDate)/60 as  diff_min

Answer 2

 select  id,system,TIMESTAMPDIFF(MINUTE,end,start) as diff_min from table_name;

Answer 3

以下查询执行此操作：

SELECT
    id,
    system,
    IF (@previousSystem = system, TIMESTAMPDIFF(MINUTE ,@previousEndTime,start), 
        @previousEndTime := 0) diff_min,
    @previousSystem := system,
    @previousEndTime := end
FROM
    system_table,
    (
        SELECT
            @previousSystem := NULL,
            @previousEndTime := '0000-00-00 00:00:00'
    ) var
ORDER BY system, id;

输出：

运行上面对给定数据的查询你将得到如下输出：

id  system      diff_min
2   system 1    0
3   system 1    1320
5   system 1    1620
6   system 2    0
7   system 2    1800

SQL FIDDLE

请忽略我查询结果集中的最后两列

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