根据 laravel 5.1 中的索引排序或 collection 或数组

Sorting or collection or array according to index in laravel 5.1

我在 laravel 中有以下 collection:

Collection {#357 ▼
  #items: array:11 [▼
    "29-04-2016" => array:2 [▼
      "posTotal" => "100"
      "posCount" => 1
    ]
    "05-05-2016" => array:6 [▼
      "posTotal" => "11"
      "posCount" => 1
      "keyedTotal" => "120"
      "keyedCount" => 1
      "cashTotal" => "32"
      "cashCount" => 2
    ]
    "10-05-2016" => array:10 [▼
      "posTotal" => "67"
      "posCount" => 4
      "keyedTotal" => "22"
      "keyedCount" => 1
      "cashcardTotal" => "123"
      "cashcardCount" => 1
      "refundTotal" => "-50"
      "refundCount" => 1
      "cashRefundTotal" => "-10"
      "cashRefundCount" => 1
    ]
    "17-05-2016" => array:2 [▶]
    "06-05-2016" => array:2 [▶]
    "16-05-2016" => array:2 [▶]
    "22-04-2016" => array:2 [▶]
    "25-04-2016" => array:2 [▶]
  ]
}

现在我想按索引对其进行排序,但需要根据日期进行转换。

例如我想展示

 "17-05-2016" => array:2 [▶]
 "10-05-2016" => array:10 [▶]
"06-05-2016" => array:2 [▶]

等等...

我尝试了 laravel 的排序 collection 方法,还尝试了 php 的 ksort 函数将 collection 转换为数组。但它把它当作一个字符串。

如果您使用的是数组,那么您可以使用带有回调函数的uksort()做空。你可以在里面写你自己的条件。

php代码:

// callback function
function cmp($a, $b){
    if(strrev($a) == strrev($b)){
        return 1;
    }
    return (strrev($a) < strrev($b)) ? -1 : 1;
}

// semple array
$test = array(
    "05-06-2015" => "1",
    "07-06-2016" => "3",
    "05-08-2016" => "4",
    "05-06-2016" => "2"    
);

uksort( $test, "cmp" );

echo "<pre>";
print_r($test);

输出:

Array
(
    [05-06-2015] => 1
    [05-06-2016] => 2
    [07-06-2016] => 3
    [05-08-2016] => 4
)