从 NbClust 中检索最佳数量的簇

Question

R 中的许多函数都提供某种控制台输出（例如 NbClust() 等）。有没有什么方法可以在不查看输出的情况下检索某些输出（例如某个整数值）？从控制台读取的任何方式？

假设输出类似于 package manual 中提供的示例代码的以下输出：

[1] "Frey index : No clustering structure in this data set"
*** : The Hubert index is a graphical method of determining the number of clusters.
                In the plot of Hubert index, we seek a significant knee that corresponds to a 
                significant increase of the value of the measure i.e the significant peak in Hubert
                index second differences plot. 

*** : The D index is a graphical method of determining the number of clusters. 
                In the plot of D index, we seek a significant knee (the significant peak in Dindex
                second differences plot) that corresponds to a significant increase of the value of
                the measure. 

******************************************************************* 
* Among all indices:                                                
* 1 proposed 2 as the best number of clusters 
* 2 proposed 4 as the best number of clusters 
* 2 proposed 6 as the best number of clusters 
* 1 proposed 7 as the best number of clusters 

                   ***** Conclusion *****                            

* According to the majority rule, the best number of clusters is  4 


*******************************************************************

如何从上述输出的最后一行检索值 4？

Answer 1

最好使用对象而不是在控制台中输出。任何 "good" 函数都会 return 希望结构化输出可以使用 $ 或 @ 符号访问，使用 str()查看对象的结构。

对于你的情况，我认为这应该可行：

length(unique(res$Best.partition))

Answer 2

另一种选择是：

max(unlist(res[4]))

从 NbClust 中检索最佳数量的簇

Retrieve best number of clusters from NbClust

r

console

console-output