okhttp 响应中的新 JsonObject

Question

我正在尝试使用 OKHttp 和 https://github.com/hongyangAndroid/okhttp-utils 来实现登录功能，但我不知道如何创建新的 JsonObject 在回调中使用 Response。

  OkHttpUtils.post()
            .url(url)
            .addParams("phone", "18681873411")
            .addParams("password", "18681873411")
            .build()
            .execute(new Callback() {
                @Override
                public Object parseNetworkResponse(Response response) throws Exception {
                    Log.i("ws","---->>parseNetworkResponse" + response.body().string());


                    JSONObject jsonObj = null;
                    try {
                        jsonObj = new JSONObject(response.body().string());
                    } catch (JSONException e) {
                        Log.i("ws","---->>JSONException");
                        e.printStackTrace();
                    } catch (IOException e) {
                        Log.i("ws","---->>IOException");
                        e.printStackTrace();
                    }
                    Log.i("ws","---->>111 :" );
                    String opCode = jsonObj.getString("OpCode");
                    String message = jsonObj.getString("Message");
                    Log.i("ws","---->>111 opCode:" + opCode);
                    Log.i("ws","---->>111 Message:" + message);
                    JSONObject result = new JSONObject();
                    result.put("qrcode",opCode);
                    result.put("message", message);
                    return result;

                }

                @Override
                public void onError(Call call, Exception e) {
                    Log.i("ws","---->>onError" + e);
                }

                @Override
                public void onResponse(Object response) {
                    Log.i("ws","---->>onResponse" + response.toString());
                }
            });

及错误信息：

parseNetworkResponse{"OpCode":0,"Message":"登陆成功","Other":{"id":1,"name":null,"phone":"18681873411","QQuid":null,"weixinuid":null,"gender":null,"age":null,"credits":null,"address":null,"signature":null,"imageurl":null,"password":"18681873411","created_at":"2016-05-19T17:05:02.000Z","updated_at":"2016-05-19T17:05:02.000Z"}}
05-20 11:29:01.953 13496-13621/com.smartspace.magicmirror I/ws: ---->>IOException
05-20 11:29:01.954 13496-13621/com.smartspace.magicmirror I/ws: ---->>111 :
05-20 11:29:01.955 13496-13496/com.smartspace.magicmirror I/ws: ---->>onErrorjava.lang.NullPointerException: Attempt to invoke virtual method 'java.lang.String org.json.JSONObject.getString(java.lang.String)' on a null object reference

Answer 1

由于调用 response.body().string() 会从 return 流中读取内容然后关闭它，所以第二次调用它。它 return 什么都不会 :\

更好的方法：

if (!response.isSuccessful()) throw new IOException("Unexpected code " + response); 
    String responseData = response.body().string();
    Log.e(TAG, "onResponse: " + responseData);
    try {
        JSONObject jsonObject = new JSONObject(responseData);
        // Do something here 
        } catch (JSONException e) {
...}

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