Python

Question

我在 Python 中有 list 个 list。我想将个人列表写成 xlwt 中的一行。

 datalist = [['India', 'Yes', '99%'], [['China', 'Yes', '89%'], ['Brazil', 'No', '90%']], ['Russia', 'Yes', '92%'], [['Germany', 'No', '97%'], ['Spain', 'No', '70%']]]

首先我计算了list的总数 def count(local_list):

def listcount(lst):
  listsum = 0
  for item in lst:
    if not isinstance(l,list):
      return 1
    else:
      listsum+= listcount(item) 

  return listsum

excel_export.py

import xlwt

book = xlwt.Workbook()
sheet = book.add_sheet("PySheet1")


for rownum in range(listcount(datalist)):
  row = sheet.row(rownum)

  for index, col in enumerate(datalist):
    # do something similar like in listcount()
    # check if instance is list if not then write the value
    # rownum will act as a row
    # column value will come from list item

    row.write(row, col, val)


book.save("test.xls")

样本表

如何在适当的行和列中写入列表值？

Answer 1

一劳永逸地处理列表的怪异结构就简单多了：

datalist = [['India', 'Yes', '99%'], [['China', 'Yes', '89%'], ['Brazil', 'No', '90%']], ['Russia', 'Yes', '92%'],
            [['Germany', 'No', '97%'], ['Spain', 'No', '70%']]]

new_datalist = []
for lst in datalist:
    if isinstance(lst[0], list):
        new_datalist.extend(lst)
    else:
        new_datalist.append(lst)
datalist = new_datalist

print(datalist)

输出：

[['India', 'Yes', '99%'], ['China', 'Yes', '89%'], ['Brazil', 'No', '90%'], ['Russia', 'Yes', '92%'], ['Germany', 'No', '97%'], ['Spain', 'No', '70%']]

现在您可以直接将值写入 sheet。你也可以去掉 listcount.

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