如何在 sql server 2008 R2 的一个查询中 运行 distinct 和 Sum

Question

我有一个 table #1，如附图所示。首先，我想对所有不同 ID 的所有数量求和。然后要显示具有相同数量的 id 的数量。

Answer 1

使用SUM和COUNT:

SELECT
    COUNT(*) AS totalId,
    qty
FROM (
    SELECT
        id, SUM(qty) AS qty
    FROM tbl
    GROUP BY id
)t
GROUP BY qty

ONLINE DEMO

Answer 2

显示所有不同 ID 的所有数量的总和：

SELECT id,SUM(qty) FROM table GROUP BY id;

显示数量相同的id

SELECT count(id),quantity FROM (SELECT id,SUM(qty) AS quantity FROM table GROUP BY id) GROUP BY quantity

Answer 3

创建临时文件后试试这个 table

create table #Temp
(
  id int, 
  qty int
)

Insert Into #Temp
SELECT  id, SUM(qty)
        FROM yourTable
        group by id

SELECT  * FROM #Temp

SELECT  Count(id) , qty
        FROM #Temp
        GROUP BY qty
        ORDER BY qty DESC