当条件满足时，while 循环不会中断

Question

我有一个 python 代码试图通过询问一些问题来猜测用户的年龄。问题是，当用户的年龄等于变量时，while 循环不会中断。这是我的代码：

age = 50
guess = raw_input("Give your age: ")
while guess != age:
  print "Are you above ",age,"?"
  x = raw_input()
  while (x != "yes") and (x != "YES") and (x != "no") and (x != "NO"):
    print "Answer with yes/YES, no/NO"
    x = raw_input()
  if (x == "yes") or (x == "YES"):
    age = 2*age-age/2
  else:
    age = age/2

  if age == guess:
    break

print "Your age is ",age

Answer 1

您需要转换为 int、raw_input returns 一个字符串，这样您就可以将 string 与 int 进行比较，后者永远不会计算为正确：

guess = int(raw_input("Give your age: "))

age == guess:
^^      ^^^
int     str

也不确定其余代码在做什么，但您可以使用 in 替换 and 的：

while x not in  {"yes","YES","no", "NO"}:

你也不需要在你的 if 语句中使用括号：

if  x == "yes" or x == "YES":

Answer 2

每次循环都要定义中断条件

在您的代码中，您只定义了一次 guess。所以它的值不会改变。

请在while循环中加入guess，使其值发生变化，达到break条件。

Answer 3

最好把无限迭代的条件改一下

# while guess != age:
while True:

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