用不同的文本长度替换字符串中不同长度的数字

Question

问题：数字的长度可能是 1、200、1000、39 99995 等，需要用文本替换，例如。 "Apple" 与数值的长度比较不同。

let str: String = "hello i have 1313 object of 10 string class with 1 object, similar to 9999 errors"

预期结果="hello i have Apple object of Apple string class with Apple object, similar to Apple errors"

我试过以下代码：

 var originalString: String = "hello i have 1313 object of 10 string class with 1 object, similar to 9999 errors"

    let strippedString: NSMutableString = NSMutableString(capacity: originalString.characters.count)
    var numArray: [String] = []
    var locArray: [NSNumber] = []
    var scanner: NSScanner = NSScanner(string:originalString)
    let numbers: NSCharacterSet = NSCharacterSet(charactersInString: "0123456789")
    while scanner.atEnd == false {
        var buffer: NSString?
        if scanner.scanCharactersFromSet(numbers, intoString: &buffer) {
            strippedString.appendString(buffer! as String)
            numArray.append(buffer! as String)
            locArray.append(scanner.scanLocation)
        }
        else {

            scanner.scanLocation = (scanner.scanLocation + 1)
        }
    }
    for (index, _) in numArray.enumerate() {
        var loc : Int = Int(locArray[index] ) - (String(numArray[index]).characters.count)
        let len = String(numArray[index]).characters.count
        let dupStr = "Apple"
        if(index != 0 && len !=  dupStr.characters.count)
        {
            loc = loc + (dupStr.characters.count - len) + 1
        }
        originalString.replaceRange(originalString.startIndex.advancedBy(loc)..<originalString.startIndex.advancedBy(loc + len), with: dupStr)
    }
    print(originalString)

Answer 1

Swift 2

NSScanner 很棒，但是如果您想要一个更简单的解决方案来完成此任务，您可以使用 componentsSeparatedByString、map、Int() 和 joinWithSeparator，如下所示：

let originalString = "hello i have 1313 object of 10 string class with 1 object, similar to 9999 errors"
let tokens = originalString.componentsSeparatedByString(" ")
let newTokens = tokens.map { (token) -> String in
    if let _ = Int(token) {
        return "Apple"
    }
    return token
}
let result = newTokens.joinWithSeparator(" ")
print(result)

打印：

hello i have Apple object of Apple string class with Apple object, similar to Apple errors

还有一个简短的映射版本：

let newTokens = tokens.map { Int([=11=]) != nil ? "Apple" : [=11=] }

Swift 3

componentsSeparatedByString(_:) 现在是 components(separatedBy:)，joinWithSeparator(_:) 现在是 joined(separator:)。

let tokens = originalString.components(separatedBy: " ")
let newTokens = tokens.map { Int([=12=]) != nil ? "Apple" : [=12=] }
let result = newTokens.joined(separator: " ")

Answer 2

var str: String = "hello i have 1313 object of 10 string class with 1 object, similar to 9999 errors"
var comp: [AnyObject] = [AnyObject](array: str.componentsSeparatedByString(" "))
for var i = 0; i < comp.count; i++ {
  var numberRegex: NSRegularExpression = NSRegularExpression.regularExpressionWithPattern("^[0-9]", options: NSRegularExpressionCaseInsensitive, error: nil)
  var regexMatch: Int = numberRegex.numberOfMatchesInString(comp[i], options: 0, range: NSMakeRange(0, (String(comp[i])).length))
    if regexMatch != 0 {
      comp[i] = "Apple"
    }
}
var result: String = comp.componentsJoinedByString(" ")
print(result)

用不同的文本长度替换字符串中不同长度的数字

Replace numeric of different length in a string with different text length

string

ios

nsscanner

swift2.2