计时子流程完成需要多长时间

Question

我目前有一个方法可以通过使用子进程调用来执行其他 python 脚本，我想知道我是否可以计算完成此过程需要多长时间？脚本在一个区间运行，我想由此实现的是检查脚本是否在该区间内完成。

def execute_scripts(script_name):
    process = sp.Popen(['python2.7', script_name])
    print 'executing - ' + script_name

Answer 1

您需要程序在脚本执行时保持运行吗？如果没有，您可以阻止您的程序执行，直到该过程完成并报告它所花费的时间：

def execute_scripts(script_name):
    time_start = time.time()
    print "starting process"
    process = sp.call(['python2.7', script_name])
    print 'finished process %s in %s s" % (process, time.time() - start_time)

Answer 2

使用timeit来计时一小段代码的执行。

#sleep2.py
import time
time.sleep(2)

您需要使用subprocess.call阻塞直到调用结束

import timeit
import subprocess as sp

def execute_scripts(script_name):
    process = sp.call(['python2.7', script_name])
    print 'executing - ' + script_name

t = timeit.Timer("execute_scripts('sleep2.py')", setup="from __main__ import execute_scripts")


print 'time taken : %f seconds' % t.timeit(1)


executing - sleep2.py
time taken : 2.032273 seconds

或者，您可以通过编写装饰器来为任何函数调用计时来概括这一点

import time
import  subprocess as sp

def timed_execution(function):
    def wrapper(arg):
        t1 = time.time()
        function(arg)
        t2 = time.time()
        return 'time taken : %f seconds' % (t2 - t1) + "\n"
   return wrapper


@timed_execution
def execute_scripts(script_name):
    sp.call(['python2.7', script_name])
    print 'executing - ' + script_name


print execute_scripts('sleep2.py')

executing - sleep2.py
time taken : 2.025291 seconds

计时子流程完成需要多长时间

Timing how long it takes for subprocess to complete

python

subprocess

python-2.7