在 neo4j 中设置决策树

Setting up a decision tree in neo4j

假设我有一个如下所示的决策树:

我已经编写了一个密码查询来创建该决策树:

create (_0 {`name`:"Spins?", `type`:"split"})

create (_1a {`name`:"Weight", `type`:"split"})
create (_1b {`name`:"Weight", `type`:"split"})

create (_2a {`name`:"Spider", `type`:"terminal"})
create (_2b {`name`:"Spider Man", `type`:"terminal"})
create (_2c {`name`:"Ant", `type`:"terminal"})
create (_2d {`name`:"Ant Man", `type`:"terminal"})

create (_0)-[:`CON` {`lt`:.5}]->(_1a)
create (_0)-[:`CON` {`gte`:.5}]->(_1b)

create (_1a)-[:`CON` {`lt`:200}]->(_2a)
create (_1a)-[:`CON` {`gte`:200}]->(_2b)

create (_1b)-[:`CON` {`lt`:200}]->(_2c)
create (_1b)-[:`CON` {`gte`:200}]->(_2d)
;

几个问题:

  1. 这是在 neo4j 中设置决策树的最佳方式吗?
  2. 我将如何编写密码查询以连接到图并获得包含输入数据的结果节点?例如假设我有数据 {'Spins?' : False, 'Weight' : 500},我将如何有效地编写查询 return "Ant Man" 节点?

允许对模型进行小的改动:

MERGE (_0:DT:Split  {name: 'Spins', l:0, i:0})
MERGE (_1a:DT:Split {name: 'Weight', l:1, i:0})
MERGE (_1b:DT:Split {name: 'Weight', l:1, i:1})

MERGE (_2a:DT:Terminal {name:'Spider', l:2, i:0})
MERGE (_2b:DT:Terminal {name:'Spider Man', l:2, i:0})
MERGE (_2c:DT:Terminal {name:'Ant', l:2, i:0})
MERGE (_2d:DT:Terminal {name:'Ant Man', l:2, i:0})

MERGE (_0)-[:DT {type:'Left', value: 0.5, propname:'Spins'}]->(_1a)
MERGE (_0)-[:DT {type:'Right', value: 0.5, propname:'Spins'}]->(_1b)
MERGE (_1a)-[:DT {type:'Left', value: 50, propname:'Weight'}]->(_2a)
MERGE (_1a)-[:DT {type:'Right', value: 50, propname:'Weight'}]->(_2b)
MERGE (_1b)-[:DT {type:'Left', value: 50, propname:'Weight'}]->(_2c)
MERGE (_1b)-[:DT {type:'Right', value: 50, propname:'Weight'}]->(_2d)

并查询:

// Input parameters:
WITH {Spins: 0.6, Weight: 500} as Cor
// Get all decision paths:
MATCH p = (S:DT:Split {l:0,i:0})-[:DT*]->(T:DT:Terminal)
// Test single decision path:
WHERE ALL(r in relationships(p) WHERE 
        (r.type='Left' AND Cor[r.propname]<r.value) OR // Left variant
        (r.type='Right' AND Cor[r.propname]>=r.value) // Right variant
      )
RETURN T