基于查找 Table 中的值的 XSLT 属性在多个 XML 输入文件的 XSLT 中动态创建

Question

我需要在查找 table 中获取由位置动态创建的值，并在遍历多个文件后将其分配给在同一转换中创建的元素。我有一个 "manifest" xml 文件，如下所示：

<?xml version="1.0" encoding="UTF-8"?>
<?xml-stylesheet type="text/xsl" href="test.xsl"?>
<files>
    <file>file1.xml</file>
    <file>file2.xml</file>
</files>

文件1和文件2如下：

文件 1：

<?xml version="1.0" encoding="UTF-8"?>
<ProductList>
    <Product>
        <Name>Schwinn Bicycle</Name>
        <Type>Bicycle</Type>
        <Quantity>2</Quantity>
        <Store>
            <Name>Some Store</Name>
            <Location>Somewhere</Location>
            <Contact>Phone Number</Contact>
        </Store>
   </Product>
    <Product>
        <Name>Huffy Bicycle</Name>
        <Type>Bicycle</Type>
        <Quantity>10</Quantity>
        <Store>
            <Name>Some Other Store</Name>
            <Location>Somewhere Else</Location>
            <Contact>Another Phone Number</Contact>
        </Store>
   </Product>
</ProductList>

文件 2：

<?xml version="1.0" encoding="UTF-8"?>
<ProductList>
    <Product>
        <Name>Expensive Bicycle Brand</Name>
        <Type>Bicycle</Type>
        <Quantity>2</Quantity>
        <Store>
            <Name>Yet Another Store</Name>
            <Location>Whole New Place</Location>
            <Contact>Completely Different Phone Number</Contact>
        </Store>
   </Product>
    <Product>
        <Name>Harley Davidson</Name>
        <Type>Motorcycle</Type>
        <Quantity>1</Quantity>
        <Store>
            <Name>Some Other Store</Name>
            <Location>Somewhere Else</Location>
            <Contact>Another Phone Number</Contact>
        </Store>
   </Product>
</ProductList>

现在我需要的是文件 XML 输出如下：

<?xml version="1.0" encoding="UTF-8"?>
<ProductList>
    <Stores>
        <Store id="1" Name="Some Store">Phone Number</Store>
        <Store id="2" Name="Some Other Store">Another Phone Number</Store>
        <Store id="3" Name="Yet Another Store">Completely Different Phone Number</Store>
    </Stores>
    <Products>
        <Product>
            <Name>Huffy Bicycle</Name>
            <StoreContact contactId="2"/>
        </Product>
        <Product>
            <Name>Schwinn Bicycle</Name>
            <StoreContact contactId="1"/>
        </Product>
        <Product>
            <Name>Expensive Bicycle Brand</Name>
            <StoreContact contactId="3"/>
        </Product>
        <Product>
            <Name>Harly Davidson</Name>
            <StoreContact contactId="2"/>
        </Product>
    </Products>

所以，总而言之，我正在浏览文件并获取联系信息，并使用它们的位置在顶部进行查找 table 以获得结果 XML。然后，我为输出创建了产品元素，并且需要以某种方式获取在我创建查找 table 时分配的 ID。我需要使用纯 XSLT 1.0。

编辑：查找中的 Id table 必须是整数值。

这是我的：

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0">
    <xsl:output method="xml" indent="yes" omit-xml-declaration="no" encoding="UTF-8"/>

    <xsl:variable name="input-docs" select="document(files/file)"/>
    <xsl:variable name="store_contacts" select="document(files/file)/ProductList/Product/Store/Contact"/>

    <xsl:template name="ProductList">
        <xsl:for-each select="$input-docs">
            <xsl:apply-templates select="Product"/>
        </xsl:for-each>
    </xsl:template>

    <xsl:template name="Contacts">
        <xsl:element name="contacts">
            <xsl:for-each select="$store_contacts">
                <xsl:if test="generate-id()=generate-id($store_contacts[normalize-space(Contact)=normalize-space(current()/Contact)][1])">
                    <xsl:element name="Store">
                        <xsl:attribute name="id"><xsl:value-of select="position()"/></xsl:attribute>
                        <xsl:value-of select="normalize-space(Contact)"/>
                    </xsl:element>
                </xsl:if>
            </xsl:for-each>
        </xsl:element>
    </xsl:template>

    <xsl:template match="/">
        <xsl:element name="ProductList">
            <xsl:element name="Stores">
                <xsl:call-template name="Contacts"/>
            </xsl:element>
            <xsl:element name="Products">
                <xsl:call-template name="ProductList"/>
            </xsl:element>
        </xsl:element>
    </xsl:template>

    <xsl:template match="Product">
        <xsl:element name="StoreContact">
            <xsl:attribute name="Name">
                <xsl:value-of select="Name"/>
            </xsl:attribute>
            <xsl:attribute name="contactId">1
                <!-- lookup value from the table created from all of the files, using the value 1 until I can figure out how to set the correct value -->
            </xsl:attribute>
        </xsl:element>
    </xsl:template>

</xsl:stylesheet>

如果这是一个重复的问题，我深表歉意，我试图找到类似的东西，但当操作员在遍历多个文件时尝试执行该功能时，没有发现任何关于该主题的问题。

Answer 1

我从你的了解到你不能使用 node-set() 扩展功能 - 这使得这非常困难。

我建议您使用 generate-id() 函数生成的唯一 ID 来 link 产品到他们的商店。

以下样式表使用 the method proposed by G. Ken Holman 生成从多个文件收集的不同商店的列表。然后我们使用相同的原理来检索每个产品的商店的唯一id：

XSLT 1.0

<xsl:stylesheet version="1.0" 
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes"/>

<xsl:variable name="input-docs" select="document(files/file)"/>
<xsl:variable name="stores" select="$input-docs/ProductList/Product/Store"/>

<xsl:template match="/">
    <ProductList>
        <Stores>
            <xsl:for-each select="$stores">
                <xsl:if test="generate-id()=generate-id($stores[Contact=current()/Contact][1])">
                    <Store id="{generate-id()}" Name="{Name}">
                        <xsl:value-of select="Contact"/>
                    </Store>
                </xsl:if>
            </xsl:for-each>     
        </Stores>
        <Products>
            <xsl:for-each select="$input-docs/ProductList/Product">
                <Product>
                    <xsl:copy-of select="Name"/>
                    <StoreContact contactId="{generate-id($stores[Contact=current()/Store/Contact][1])}"/>
                </Product>          
            </xsl:for-each>     
        </Products>
    </ProductList>      
</xsl:template>

</xsl:stylesheet>

实际结果可能因处理器而略有不同 - 以下是 Saxon 6.5 生成的示例：

<?xml version="1.0" encoding="UTF-8"?>
<ProductList>
   <Stores>
      <Store id="d1e14" Name="Some Store">Phone Number</Store>
      <Store id="d1e38" Name="Some Other Store">Another Phone Number</Store>
      <Store id="d2e14" Name="Yet Another Store">Completely Different Phone Number</Store>
   </Stores>
   <Products>
      <Product>
         <Name>Schwinn Bicycle</Name>
         <StoreContact contactId="d1e14"/>
      </Product>
      <Product>
         <Name>Huffy Bicycle</Name>
         <StoreContact contactId="d1e38"/>
      </Product>
      <Product>
         <Name>Expensive Bicycle Brand</Name>
         <StoreContact contactId="d2e14"/>
      </Product>
      <Product>
         <Name>Harley Davidson</Name>
         <StoreContact contactId="d1e38"/>
      </Product>
   </Products>
</ProductList>

Answer 2

这是一个完整的解决方案，可以生成有意义的整数 ID:

<xsl:stylesheet version="1.0"  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>

 <xsl:variable name="vAllDocs" select="document(/*/*)"/>

 <xsl:variable name="vAllStores" select="$vAllDocs/*/*/Store"/>

 <xsl:variable name="vPositionsOfDistinct">
   <xsl:for-each select="$vAllStores">
     <xsl:variable name="vCur" select="."/>
     <xsl:if test=
      "generate-id() 
     = generate-id($vAllStores[concat(Name,'|',Location,'|',Contact) 
                             = concat($vCur/Name,'|',$vCur/Location,'|',$vCur/Contact)]
                                [1])">
       <xsl:value-of select="concat('|', position())"/>
     </xsl:if>
   </xsl:for-each>
   <xsl:text>|</xsl:text>
 </xsl:variable>

 <xsl:variable name="vDistinctStores" select=
 "$vAllStores[contains($vPositionsOfDistinct, concat('|',position(),'|'))]"/>

  <xsl:template match="/">
    <ProductList>
      <Stores>
        <xsl:apply-templates select="$vAllStores" mode="distinct"/>
      </Stores>
      <Products><xsl:apply-templates select="$vAllDocs/*/Product"/></Products>
    </ProductList>
  </xsl:template>

  <xsl:template match="Store" mode="distinct">
    <xsl:if test="contains($vPositionsOfDistinct, concat('|',position(),'|'))">
      <Store id="{position()}" Name="{Name}"><xsl:value-of select="Contact"/></Store>
    </xsl:if>
  </xsl:template>

  <xsl:template match="Product">
     <xsl:variable name="vCur" select="Store"/>
     <xsl:variable name="vPos">
       <xsl:for-each select="$vAllStores">
             <xsl:if test=
                "contains($vPositionsOfDistinct, concat('|',position(),'|'))
               and
                 concat(Name,'|',Location,'|',Contact) 
               = concat($vCur/Name,'|', $vCur/Location,'|', $vCur/Contact)
                ">
               <xsl:value-of select="position()"/>
             </xsl:if>
       </xsl:for-each>
     </xsl:variable>

   <Product>
     <xsl:copy-of select="Name"/>
     <StoreContact contactId="{$vPos}"/>
   </Product>
  </xsl:template>
</xsl:stylesheet>

应用于所提供的 XML 文档时:

<files>
    <file>afile1.xml</file>
    <file>afile2.xml</file>
</files>

和提供的两个 XML 文件（两个产品重新排序以显示更有趣的情况，当生成的商店 ID 不是连续整数时）：

afile1.xml:

<ProductList>
    <Product>
        <Name>Schwinn Bicycle</Name>
        <Type>Bicycle</Type>
        <Quantity>2</Quantity>
        <Store>
            <Name>Some Store</Name>
            <Location>Somewhere</Location>
            <Contact>Phone Number</Contact>
        </Store>
    </Product>
    <Product>
        <Name>Huffy Bicycle</Name>
        <Type>Bicycle</Type>
        <Quantity>10</Quantity>
        <Store>
            <Name>Some Other Store</Name>
            <Location>Somewhere Else</Location>
            <Contact>Another Phone Number</Contact>
        </Store>
    </Product>
</ProductList>

afile2.xml:

<ProductList>
    <Product>
        <Name>Expensive Bicycle Brand</Name>
        <Type>Bicycle</Type>
        <Quantity>2</Quantity>
        <Store>
            <Name>Some Other Store</Name>
            <Location>Somewhere Else</Location>
            <Contact>Another Phone Number</Contact>
        </Store>
    </Product>
    <Product>
        <Name>Harley Davidson</Name>
        <Type>Motorcycle</Type>
        <Quantity>1</Quantity>
        <Store>
            <Name>Yet Another Store</Name>
            <Location>Whole New Place</Location>
            <Contact>Completely Different Phone Number</Contact>
        </Store>
    </Product>
</ProductList>

然后产生了想要的正确结果:

<ProductList>
   <Stores>
      <Store id="1" Name="Some Store">Phone Number</Store>
      <Store id="2" Name="Some Other Store">Another Phone Number</Store>
      <Store id="4" Name="Yet Another Store">Completely Different Phone Number</Store>
   </Stores>
   <Products>
      <Product>
         <Name>Schwinn Bicycle</Name>
         <StoreContact contactId="1"/>
      </Product>
      <Product>
         <Name>Huffy Bicycle</Name>
         <StoreContact contactId="2"/>
      </Product>
      <Product>
         <Name>Expensive Bicycle Brand</Name>
         <StoreContact contactId="2"/>
      </Product>
      <Product>
         <Name>Harley Davidson</Name>
         <StoreContact contactId="4"/>
      </Product>
   </Products>
</ProductList>

基于查找 Table 中的值的 XSLT 属性在多个 XML 输入文件的 XSLT 中动态创建

XSLT attribute based on value in Lookup Table created dynamically in XSLT over multiple XML input files

xslt-1.0

xslt-grouping