OPENXML 没有 return 预期的结果

Question

我有一个XML

<response>
  <message_infos>
    <message_info>
      <id>397300589</id>
      <pdu_id>673399673</pdu_id>
      <status>12</status>
      <id>397300589</id>
      <pdu_id>673399675</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>397300591</id>
      <pdu_id>673399669</pdu_id>
      <status>12</status>
      <id>397300591</id>
      <pdu_id>673399671</pdu_id>
      <status>12</status>
    </message_info>
  </message_infos>
</response>

我需要另存为

397300589   673399673   12
397300589   673399675   12
397300591   673399669   12
397300591   673399671   12

但是

SELECT *
FROM OPENXML(@ixml, '/response/message_infos/message_info')
WITH (id VARCHAR(50) 'id', pdu_id VARCHAR(50) 'pdu_id', status INT 'status')

给我错误的结果：

397300589   673399673   12
397300591   673399669   12

我做错了什么？我没有找到相同的示例，有人可以帮助我吗？

Answer 1

首先：FROM OPENXML已经过时了！你最好使用 real XML 方法...

更新

根据您的评论，我建议这样做：您阅读编号集中的所有标签，并将它们与它们在子集中的索引拼在一起。

我在第二组中添加了第三组 message_info 来测试这个...

DECLARE @ixml XML=
'<response>
  <message_infos>
    <message_info>
      <id>397300589</id>
      <pdu_id>673399673</pdu_id>
      <status>12</status>
      <id>397300589</id>
      <pdu_id>673399675</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>397300591</id>
      <pdu_id>673399669</pdu_id>
      <status>12</status>
      <id>397300591</id>
      <pdu_id>673399671</pdu_id>
      <status>12</status>
      <id>1111</id>
      <pdu_id>2222</pdu_id>
      <status>33</status>
    </message_info>
  </message_infos>
</response>';

WITH AllMessageInfos AS
(
    SELECT  ROW_NUMBER() OVER(ORDER BY(SELECT NULL)) AS Mi_Index
           ,mi.query('.') AS TheMI
    FROM @ixml.nodes('/response/message_infos/message_info') AS A(mi)
)
,AllIDs AS
(
    SELECT Mi_Index
          ,ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS id_Index
          ,id.value('.','bigint') AS id
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/id') AS a(id)   
)
,AllPdu_IDs AS
(
    SELECT Mi_Index
          ,ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS pdu_Index
          ,id.value('.','bigint') AS pdu_id
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/pdu_id') AS a(id)   
)
,AllStatus AS
(
    SELECT Mi_Index
          ,ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS status_Index
          ,id.value('.','int') AS status
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/status') AS a(id)   
)
SELECT i.Mi_Index AS MessageInfoIndex
      ,i.id_Index AS SubSetIndex
      ,i.id
      ,p.pdu_id
      ,s.status
FROM AllIDs AS i
INNER JOIN AllPdu_IDs AS p ON i.Mi_Index=p.Mi_Index AND i.id_Index=p.pdu_Index
INNER JOIN AllStatus AS s ON i.Mi_Index=s.Mi_Index AND i.id_Index=s.status_Index

上一个

似乎很奇怪，每个标签下面都有两组相同的标签message_info。你可以这样做：

DECLARE @ixml XML=
'<response>
  <message_infos>
    <message_info>
      <id>397300589</id>
      <pdu_id>673399673</pdu_id>
      <status>12</status>
      <id>397300589</id>
      <pdu_id>673399675</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>397300591</id>
      <pdu_id>673399669</pdu_id>
      <status>12</status>
      <id>397300591</id>
      <pdu_id>673399671</pdu_id>
      <status>12</status>
    </message_info>
  </message_infos>
</response>';

SELECT m.value('id[1]','bigint') AS id
      ,m.value('pdu_id[1]','bigint') AS pdu_id
      ,m.value('status[1]','int') AS status
FROM @ixml.nodes('/response/message_infos/message_info') AS A(m)
UNION ALL
SELECT m.value('id[2]','bigint') AS id
      ,m.value('pdu_id[2]','bigint') AS pdu_id
      ,m.value('status[2]','int') AS status
FROM @ixml.nodes('/response/message_infos/message_info') AS A(m)

Answer 2

DECLARE @xml XML = N'
<response>
  <message_infos>
    <message_info>
      <id>397300589</id>
      <pdu_id>673399673</pdu_id>
      <status>12</status>
      <id>397300589</id>
      <pdu_id>673399675</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>397300591</id>
      <pdu_id>673399669</pdu_id>
      <status>12</status>
      <id>397300591</id>
      <pdu_id>673399671</pdu_id>
      <status>12</status>
    </message_info>
  </message_infos>
</response>'

SELECT
      id = MIN(CASE WHEN RowNumGroup = 1 THEN val END)
    , pdu_id = MIN(CASE WHEN RowNumGroup = 2 THEN val END)
    , [status] = MIN(CASE WHEN RowNumGroup = 0 THEN val END)
FROM (
    SELECT
          val = t.c.value('(./text())[1]', 'BIGINT')
        , RowNum = ROW_NUMBER() OVER (ORDER BY 1/0)
        , RowNumGroup = ROW_NUMBER() OVER (ORDER BY 1/0) % 3
    FROM @xml.nodes('/response/message_infos/message_info/*') t(c)
) t
GROUP BY RowNum - CASE WHEN RowNumGroup = 0 THEN 3 ELSE RowNumGroup END

2016 年 5 月 30 日更新

准备资料：

SET NOCOUNT ON
IF OBJECT_ID('tempdb.dbo.#xml') IS NOT NULL
    DROP TABLE #xml
GO
CREATE TABLE #xml (data XML)
GO
INSERT INTO #xml
SELECT TOP(10000) N'
<response>
  <message_infos>
    <message_info>
      <id>397300589</id>
      <pdu_id>673399673</pdu_id>
      <status>12</status>
      <id>397300589</id>
      <pdu_id>673399675</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>397300591</id>
      <pdu_id>673399669</pdu_id>
      <status>12</status>
      <id>397300591</id>
      <pdu_id>673399671</pdu_id>
      <status>12</status>
    </message_info>
  </message_infos>
</response>'
FROM [master].dbo.spt_values

迈克尔·埃里克森

DECLARE @d DATETIME = GETDATE()

SELECT T.X.value('(id/text())[sql:column("N.N")][1]', 'INT') AS id,
       T.X.value('(pdu_id/text())[sql:column("N.N")][1]', 'INT') AS pdu_id,
       T.X.value('(status/text())[sql:column("N.N")][1]', 'INT') AS [status]
FROM #xml x
CROSS APPLY data.nodes('/response/message_infos/message_info') AS T(X)
CROSS APPLY (
    VALUES
        (1),(2),(3),(4),(5),
        (6),(7),(8),(9),(10)
) AS N(N)
WHERE N.N <= T.X.value('count(id)', 'INT')

SELECT 'Mikael Eriksson: ' +  CAST(CAST(GETDATE() - @d AS TIME) AS VARCHAR(100))
GO

Shnugo

DECLARE @d DATETIME = GETDATE()

WITH AllMessageInfos AS (
    SELECT ROW_NUMBER() OVER(ORDER BY(SELECT NULL)) AS Mi_Index
         , mi.query('.') AS TheMI
    FROM #xml x
    CROSS APPLY data.nodes('/response/message_infos/message_info') AS A(mi)
)
, AllIDs AS (
    SELECT Mi_Index
         , ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS id_Index
         , id.value('.','NVARCHAR(MAX)') AS id
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/id') AS a(id)   
)
, AllPdu_IDs AS (
    SELECT Mi_Index
         , ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS pdu_Index
         , id.value('.','NVARCHAR(MAX)') AS pdu_id
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/pdu_id') AS a(id)   
)
, AllStatus AS (
    SELECT Mi_Index
         , ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS status_Index
         , id.value('.', 'INT') AS status
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/status') AS a(id)   
)
SELECT i.Mi_Index AS MessageInfoIndex
     , i.id_Index AS SubSetIndex
     , i.id
     , p.pdu_id
     , s.[status]
FROM AllIDs AS i
JOIN AllPdu_IDs AS p ON i.Mi_Index = p.Mi_Index AND i.id_Index = p.pdu_Index
JOIN AllStatus AS s ON i.Mi_Index = s.Mi_Index AND i.id_Index = s.status_Index

SELECT 'Shnugo: ' +  CAST(CAST(GETDATE()-@d AS TIME) AS VARCHAR(100))
GO

蒙泰维兹多

DECLARE @d DATETIME = GETDATE()

SELECT 
    m.value('for $i in . return count(../../*[. << $i])', 'INT') AS message_info_position,
    m.value('for $i in . return count(../*[. << $i]) + 1', 'INT') AS internal_position,
    m.value('fn:local-name(.)', 'SYSNAME') AS element_name,
    m.value('.', 'NVARCHAR(4000)') AS element_value
FROM #xml x
CROSS APPLY data.nodes('/response/message_infos/message_info/*') AS A(m)

SELECT 'Montewhizdoh: ' +  CAST(CAST(GETDATE()-@d AS TIME) AS VARCHAR(100))
GO

Devart（旧）

DECLARE @d DATETIME = GETDATE()
SELECT
      id = MAX(CASE WHEN name = 'id' THEN val END)
    , pdu_id = MAX(CASE WHEN name = 'pdu_id' THEN val END)
    , [status] = MAX(CASE WHEN name = 'status' THEN val END)
FROM (
    SELECT
          name = t.c.value('local-name(.)', 'SYSNAME')
        , val = t.c.value('.', 'INT')
        , RowNum = ROW_NUMBER() OVER (ORDER BY 1/0)
        , RowNumGroup = ROW_NUMBER() OVER (ORDER BY 1/0) % 3
    FROM #xml x
    CROSS APPLY data.nodes('/response/message_infos/message_info/*') t(c)
) t
GROUP BY RowNum - CASE WHEN RowNumGroup = 0 THEN 3 ELSE RowNumGroup END
SELECT 'Devart (OLD): ' +  CAST(CAST(GETDATE()-@d AS TIME) AS VARCHAR(100))
GO

Devart（新）

DECLARE @d DATETIME = GETDATE()
SELECT
      id = MIN(CASE WHEN RowNumGroup = 1 THEN val END)
    , pdu_id = MIN(CASE WHEN RowNumGroup = 2 THEN val END)
    , [status] = MIN(CASE WHEN RowNumGroup = 0 THEN val END)
FROM (
    SELECT
          val = t.c.value('(./text())[1]', 'BIGINT')
        , RowNum = ROW_NUMBER() OVER (ORDER BY 1/0)
        , RowNumGroup = ROW_NUMBER() OVER (ORDER BY 1/0) % 3
    FROM #xml x
    CROSS APPLY data.nodes('/response/message_infos/message_info/*') t(c)
) t
GROUP BY RowNum - CASE WHEN RowNumGroup = 0 THEN 3 ELSE RowNumGroup END

SELECT 'Devart (NEW): ' +  CAST(CAST(GETDATE()-@d AS TIME) AS VARCHAR(100))

性能比较 (Core i5 4460 3.2GHz, DDR3 8Gb, SQL Server 2014 SP1 Express):

Mikael Eriksson: 00:00:00.327
Shnugo:          00:00:00.913
Montewhizdoh:    00:00:01.680
Devart (OLD):    00:00:00.363
Devart (NEW):    00:00:00.200

Answer 3

我提出以下建议供您考虑。您可能需要调整结果，但结果具有足够的意义以按原样进行编程。

message_info_position 告诉您 message_info 值来自什么以及 local_position 告诉你在 message_info

中的位置

我认为您会发现此解决方案相当强大并且能够处理数据的奇怪形状。

希望对您有所帮助！

DECLARE @ixml XML=
'<response>
  <message_infos>
    <message_info>
      <id>397300589</id>
      <pdu_id>673399673</pdu_id>
      <status>12</status>
      <id>397300589</id>
      <pdu_id>673399675</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>397300591</id>
      <pdu_id>673399669</pdu_id>
      <id>397300591</id>
      <pdu_id>673399671</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>3973005891</id>
      <pdu_id>6733996732</pdu_id>
      <status>123</status>
      <id>3973005894</id>
      <pdu_id>6733996755</pdu_id>
      <status>126</status>
      <id>3973005897</id>
      <pdu_id>6733996738</pdu_id>
      <status>129</status>
      <id>39730058912</id>
      <pdu_id>67339967513</pdu_id>
    <pdu_id>67339967513x</pdu_id>
    <pdu_id>67339967513y</pdu_id>
      <status>12</status>
    </message_info>
  </message_infos>
</response>';

SELECT 
 row_number() over(order by A.m) as internal_position,
 CHECKSUM(m.value('..', 'nvarchar(max)')) as message_info_position,
 m.value('fn:local-name(.)', 'SYSNAME') as element_name,
 m.value('.', 'nvarchar(4000)') as element_value
FROM @ixml.nodes('/response/message_infos/message_info/*') AS A(m)

Answer 4

您可以使用数字 table 来获取 n:th 值。这当然不依赖于未定义的语句顺序，但它确实要求所有元素在每个 message_info 元素中出现的次数相等。

这里我使用了 10 行的静态数字 table。

select T.X.value('(id/text())[sql:column("N.N")][1]', 'int') as id,
       T.X.value('(pdu_id/text())[sql:column("N.N")][1]', 'int') as pdu_id,
       T.X.value('(status/text())[sql:column("N.N")][1]', 'int') as status
from @x.nodes('/response/message_infos/message_info') as T(X)
  cross apply (values(1),(2),(3),(4),(5),(6),(7),(8),(9),(10)) as N(N)
where N.N <= T.X.value('count(id)', 'int')

Answer 5

这不是答案，只是性能比较！

我真正喜欢 SO 的是不同人提供的各种解决方案。这里有 4 个答案，每个答案都遵循一个完全不同的概念。

我很好奇他们的表现。这是我的结果：

Mikael Eriksson 约 1.4 秒
Shnugo 约 4.8 秒
montewhizdoh 在 8.8 秒内 但尚未旋转！！
11.3 秒后完成

由于采用了所有节点，通过 XML 自上而下 读取的方法显然比具有大量来回导航的方法更快。可能是，可以改进一些解决方案...

令我惊讶的是，GROUP BY with MAX and CASE 速度很慢...

这是代码：

CREATE TABLE #tmp (ID INT IDENTITY,XmlContent XML);
GO
INSERT INTO #tmp(XmlContent)
SELECT('<response>
  <message_infos>
    <message_info>
      <id>397300589</id>
      <pdu_id>673399673</pdu_id>
      <status>12</status>
      <id>397300589</id>
      <pdu_id>673399675</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>397300591</id>
      <pdu_id>673399669</pdu_id>
      <status>12</status>
      <id>397300591</id>
      <pdu_id>673399671</pdu_id>
      <status>12</status>
    </message_info>
    <message_info>
      <id>3973005891</id>
      <pdu_id>6733996732</pdu_id>
      <status>123</status>
      <id>3973005894</id>
      <pdu_id>6733996755</pdu_id>
      <status>126</status>
      <id>3973005897</id>
      <pdu_id>6733996738</pdu_id>
      <status>129</status>
      <id>39730058912</id>
      <pdu_id>67339967513</pdu_id>
      <status>12</status>
    </message_info>
  </message_infos>
</response>');
GO 1000


--Mikael Eriksson 1,4
DECLARE @d DATETIME = GETDATE();
WITH Numbers AS (SELECT N FROM (VALUES(1),(2),(3),(4),(5),(6),(7),(8),(9),(10)) as tbl(N)) 
select T.X.value('(id/text())[sql:column("N.N")][1]', 'nvarchar(max)') as id,
       T.X.value('(pdu_id/text())[sql:column("N.N")][1]', 'nvarchar(max)') as pdu_id,
       T.X.value('(status/text())[sql:column("N.N")][1]', 'int') as status
from #tmp
CROSS APPLY XmlContent.nodes('/response/message_infos/message_info') as T(X)
  cross apply (SELECT TOP(T.X.value('count(id)', 'int')) N FROM Numbers) AS N(N)

SELECT 'Mikael Eriksson: ' +  CAST(CAST(GETDATE()-@d AS TIME) AS VARCHAR(100));
GO

--Shnugo 4.8 Sekunden
DECLARE @d DATETIME = GETDATE();
WITH AllMessageInfos AS
(
    SELECT  ROW_NUMBER() OVER(ORDER BY(SELECT NULL)) AS Mi_Index
           ,mi.query('.') AS TheMI
    FROM #tmp
    CROSS APPLY XmlContent.nodes('/response/message_infos/message_info') AS A(mi)
)
,AllIDs AS
(
    SELECT Mi_Index
          ,ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS id_Index
          ,id.value('.','nvarchar(max)') AS id
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/id') AS a(id)   
)
,AllPdu_IDs AS
(
    SELECT Mi_Index
          ,ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS pdu_Index
          ,id.value('.','nvarchar(max)') AS pdu_id
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/pdu_id') AS a(id)   
)
,AllStatus AS
(
    SELECT Mi_Index
          ,ROW_NUMBER() OVER(PARTITION BY Mi_Index ORDER BY (SELECT NULL)) AS status_Index
          ,id.value('.','int') AS status
    FROM AllMessageInfos
    CROSS APPLY TheMI.nodes('message_info/status') AS a(id)   
)
SELECT i.Mi_Index AS MessageInfoIndex
      ,i.id_Index AS SubSetIndex
      ,i.id
      ,p.pdu_id
      ,s.status
FROM AllIDs AS i
INNER JOIN AllPdu_IDs AS p ON i.Mi_Index=p.Mi_Index AND i.id_Index=p.pdu_Index
INNER JOIN AllStatus AS s ON i.Mi_Index=s.Mi_Index AND i.id_Index=s.status_Index

SELECT 'Shnugo: ' +  CAST(CAST(GETDATE()-@d AS TIME) AS VARCHAR(100));
GO

--Montewizdoh 8.8 Sekunden
DECLARE @d DATETIME = GETDATE();
SELECT 
m.value('for $i in . return count(../../*[. << $i])', 'int') as message_info_position,
m.value('for $i in . return count(../*[. << $i]) + 1', 'int') as internal_position,
m.value('fn:local-name(.)', 'SYSNAME') as element_name,
m.value('.', 'nvarchar(4000)') as element_value
FROM #tmp
CROSS APPLY XmlContent.nodes('/response/message_infos/message_info/*') AS A(m)
SELECT 'Montewhizdoh: ' +  CAST(CAST(GETDATE()-@d AS TIME) AS VARCHAR(100));
GO

--Devart 11.3 Sec
DECLARE @d DATETIME = GETDATE();
SELECT
      id = MAX(CASE WHEN name = 'id' THEN val END)
    , pdu_id = MAX(CASE WHEN name = 'pdu_id' THEN val END)
    , [status] = MAX(CASE WHEN name = 'status' THEN val END)
FROM (
    SELECT
          name = t.c.value('local-name(.)', 'SYSNAME')
        , val = t.c.value('.', 'nvarchar(max)')
        , RowNum = ROW_NUMBER() OVER (ORDER BY 1/0)
        , RowNumGroup = ROW_NUMBER() OVER (ORDER BY 1/0) % 3
    FROM #tmp
    CROSS APPLY XmlContent.nodes('/response/message_infos/message_info/*') t(c)
) t
GROUP BY RowNum - CASE WHEN RowNumGroup = 0 THEN 3 ELSE RowNumGroup END
SELECT 'Devart: ' +  CAST(CAST(GETDATE()-@d AS TIME) AS VARCHAR(100));

GO

DROP TABLE #tmp;

OPENXML 没有 return 预期的结果

OPENXML does not return the expected result

sql-server

xml

tsql

xquery

openxml

更新

上一个

这不是答案，只是性能比较！