fsolve 不适用于参数化函数句柄

Question

例如，我定义了以下函数句柄：

F = @(x, y, z)[x+y+z; x*y*z];  
funcc = @(x, y)F(x, y, 0);

来电

res = fsolve(funcc, [10; 10]);

导致错误：

Error using @(x,y)F(x,y,0)
Not enough input arguments.

Error in fsolve (line 219)
        fuser = feval(funfcn{3},x,varargin{:});

Caused by:
Failure in initial user-supplied objective function evaluation. FSOLVE cannot continue.

我该如何解决？

Answer 1

请重新阅读requirements for the objective function in the documentation。该函数必须采用单个矢量输入和 return 一个矢量。您正在尝试传递两个标量。相反：

F = @(x, y, z)[x+y+z; x*y*z];
funcc = @(x)F(x(1), x(2), 0);

objective 函数的输入应与您的初始猜测一致，x0 ([10; 10])。

fsolve 不适用于参数化函数句柄

fsolve doesn't work with parametrized function handles

matlab

numerical

solver