在不解压的情况下读取 zip 文件的内容
Reading contents of zip file without extracting
我正在努力实现的示例:
我的文本文件 (test1.txt
) 包含以下两行:
John scored 80 in english
tim scored 75 in english
我已将此文件压缩为 test1.zip
,我正在尝试使用以下代码读取内容:
f = 'test1.zip'
z = zipfile.ZipFile(f, "r")
zinfo = z.namelist()
for name in zinfo:
with z.open(name) as f1:
fi1 = f1.readlines()
for line in fi1:
print(line)
但我得到的结果是
b'John scored 80 in english\r\n'
b'tim scored 75 in english\r\n'
我如何读取这个 zip 文件的内容,它应该给我与原始文件内容相同的输出,即:
John scored 80 in english
tim scored 75 in english
您实际上正在阅读文件中的确切内容。
/r/n字符是windows中的换行符。问题
Difference between \n and \r? 更详细一些,但归结为 Windows 使用 /r/n 作为换行符。
您看到的 b' 字符与 python 及其解析文件的方式有关。问题 What does the 'b' character do in front of a string literal? 很好地回答了为什么会发生这种情况,但引用的文档是:
Bytes literals are always prefixed with 'b' or 'B'; they produce an
instance of the bytes type instead of the str type. They may only
contain ASCII characters; bytes with a numeric value of 128 or greater
must be expressed with escapes.
编辑:我实际上找到了一个非常相似的答案,您可以从中提取阅读而无需额外字符:py3k: How do you read a file inside a zip file as text, not bytes?。基本想法是你可以使用这个:
items_file = io.TextIOWrapper(items_file, encoding='your-encoding', newline='')
使用print(line.decode('ascii').strip())
代替print(line)
我正在努力实现的示例:
我的文本文件 (test1.txt
) 包含以下两行:
John scored 80 in english
tim scored 75 in english
我已将此文件压缩为 test1.zip
,我正在尝试使用以下代码读取内容:
f = 'test1.zip'
z = zipfile.ZipFile(f, "r")
zinfo = z.namelist()
for name in zinfo:
with z.open(name) as f1:
fi1 = f1.readlines()
for line in fi1:
print(line)
但我得到的结果是
b'John scored 80 in english\r\n'
b'tim scored 75 in english\r\n'
我如何读取这个 zip 文件的内容,它应该给我与原始文件内容相同的输出,即:
John scored 80 in english
tim scored 75 in english
您实际上正在阅读文件中的确切内容。
/r/n字符是windows中的换行符。问题 Difference between \n and \r? 更详细一些,但归结为 Windows 使用 /r/n 作为换行符。
您看到的 b' 字符与 python 及其解析文件的方式有关。问题 What does the 'b' character do in front of a string literal? 很好地回答了为什么会发生这种情况,但引用的文档是:
Bytes literals are always prefixed with 'b' or 'B'; they produce an instance of the bytes type instead of the str type. They may only contain ASCII characters; bytes with a numeric value of 128 or greater must be expressed with escapes.
编辑:我实际上找到了一个非常相似的答案,您可以从中提取阅读而无需额外字符:py3k: How do you read a file inside a zip file as text, not bytes?。基本想法是你可以使用这个:
items_file = io.TextIOWrapper(items_file, encoding='your-encoding', newline='')
使用print(line.decode('ascii').strip())
代替print(line)