php 抽象类和接口

Question

我有以下场景：

    abstract class Contractor {
     // Generic contractor methods...         
    }

    abstract class PrivatePerson extends Contractor {
     // Adds methods specific to private contractors
    }

     abstract class Company extends Contractor {
     // Adds methods specific to Company contractors
    }

    class CustomerPrivate extends PrivatePerson {
     // Customers that are contractors, but physical persons
    }

   class CustomerCompany extends Company {
     // Customers that are contractors, but companies
    }

供应商和经销商也是如此，他们可以是私人，也可以是公司。现在的问题如下：如何强制 class CustomerPrivate 和 CustomerCompany 的对象同时成为 class Customer（我还没有定义）的对象，供应商和经销商也一样.在这种情况下使用接口是一种好习惯吗？

    interface Customer {
    }

     class PrivateCustomer extends PrivatePerson implements Customer {
     // Customers that are physical persons, but are CUSTOMERS!
    }

感谢任何建议！

Answer 1

方法一

class CustomerPrivate extends PrivatePerson
{
    public function __construct()
    {
        if( $this instanceof Customer )
        {
            //CODE
        }
        else
        {
            throw new \Exception("YOU ERROR MESSAGE", 1);
            # code...
        }
    }
}

方法二

$obj = new CustomerPrivate();

if ($obj instanceof Customer)
{
   //CODE
}
else
{
    # code...
}

您可以对任何 class 执行此操作

已编辑

是的，你可以像你发布的那样连接

interface Customer
{
}

class PrivateCustomer extends PrivatePerson implements Customer
{
     // Customers that are physical persons, but are CUSTOMERS!
}

或

你可以使用特质。特征非常灵活，但仅在 PHP 5.4 或更高版本

中受支持

trait Customer
{

}

class PrivateCustomer extends PrivatePerson
{
    use Customer; //trait customer
    use OtherTrait;

  // Customers that are physical persons, but are CUSTOMERS!
}

编辑 2

根据您的情况，有不同的算法可以解决您的问题。我无法想象整个场景，但从你的问题来看。你想让 Customer 类型在两个不同的树（ Person 和 Company ）中通用，在这种情况下线性层次结构是一个问题，所以我可能使用了这样的东西。

abstract class Contractor
{
    public function isCustomer()
    {
        return FALSE;
    }
}


trait Customer
{
    public function isCustomer()
    {
        return TRUE;
    }
}

class CustomerCompany extends Company
{
    \use Customer;

    public function __construct()
    {
        if( !$this->isCustomer() )
        {
            throw new \Exception('ERROR', 1);
        }
    }
}

Answer 2

好的。我终于明白了！

    Trait CustomerTrait {   

    }

    interface Customer {    

    }

    class CustomerCompany extends Company implements Customer { 

       use CustomerTrait;
    }   

   class CustomerPrivate extends ContractorPrivate implements Customer { 

       use CustomerTrait;
   }

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