在 PHPUnit 中验证 HTTP 响应代码

Question

我正在为 return HTTP 响应代码的几种方法编写单元测试。我找不到断言 HTTP 响应代码的方法。也许我遗漏了一些明显的东西，或者我对 PHPUnit 有一些误解。

我正在使用 PHPUnit 4.5 稳定版。

class 消息的相关部分：

public function validate() {
  // Decode JSON to array.
  if (!$json = json_decode($this->read(), TRUE)) {      
    return http_response_code(415);
  }
  return $json;
}

// Abstracted file_get_contents a bit to facilitate unit testing.
public $_file_input = 'php://input';

public function read() {
  return file_get_contents($this->_file_input);
}

单元测试：

// Load invalid JSON file and verify that validate() fails.
public function testValidateWhenInvalid() {
  $stub1 = $this->getMockForAbstractClass('Message');
  $path =  __DIR__ . '/testDataMalformed.json';
  $stub1->_file_input = $path;
  $result = $stub1->validate();
  // At this point, we have decoded the JSON file inside validate() and have expected it to fail.
  // Validate that the return value from HTTP 415.
  $this->assertEquals('415', $result);
}

PHP单位returns:

1) MessageTest::testValidateWhenInvalid
Failed asserting that 'true' matches expected '415'.

我不确定为什么 $result 是 returning 'true' 。 . .特别是作为字符串值。也不确定我的 'expected' 参数应该是什么。

Answer 1

According to the docs 可以调用不带参数的http_response_code()方法来接收当前的响应码。

<?php

http_response_code(401);
echo http_response_code(); //Output: 401

?>

因此您的测试应该如下所示：

public function testValidateWhenInvalid() {
    $stub1 = $this->getMockForAbstractClass('Message');
    $path =  __DIR__ . '/testDataMalformed.json';
    $stub1->_file_input = $path;
    $result = $stub1->validate();
    // At this point, we have decoded the JSON file inside validate() and have expected it to fail.
    // Validate that the return value from HTTP 415.
    $this->assertEquals(415, http_response_code()); //Note you will get an int for the return value, not a string
}

在 PHPUnit 中验证 HTTP 响应代码

Validating HTTP Response Codes in PHPUnit

php

phpunit

unit-testing