将文件上传到 Java 中没有临时文件的 HTTP 服务器内存?
Upload a file to an HTTP Server Memory in Java without temporal files?
如何在 Java 中不使用临时文件直接将文件上传到 HTTP 服务器内存?
我目前在 tomcat 上使用 Struts 2 和 apache ServletFileUpload,但我还没有找到实现此目的的方法。
在 apache 中,class FileUploadBase parseRequest(RequestContext ctx)... 正在创建临时文件
public List<FileItem> parseRequest(RequestContext ctx)
...
Streams.copy(item.openStream(), fileItem.getOutputStream(), true);
基于此文档 here 我编写了以下 servlet 以在不创建临时文件的情况下上传到字节数组。
import java.io.IOException;
import java.io.InputStream;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItemIterator;
import org.apache.commons.fileupload.FileItemStream;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.fileupload.util.Streams;
import org.apache.commons.io.IOUtils;
@WebServlet("/upload")
public class UploadByteArrayServlet extends HttpServlet {
private static final long serialVersionUID = 1123445L;
private static final int MAX_FILE_SIZE = 1024 * 1024 * 1; // 1MB
private static final int MAX_REQUEST_SIZE = 1024 * 1024 * 1; // 1MB
protected void doPost(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
byte[] bytes = "".getBytes();
boolean isMultipart = ServletFileUpload.isMultipartContent(request);
if(isMultipart){
ServletFileUpload upload = new ServletFileUpload();
upload.setFileSizeMax(MAX_FILE_SIZE);
upload.setSizeMax(MAX_REQUEST_SIZE);
try {
// Parse the request
FileItemIterator iter = upload.getItemIterator(request);
while (iter.hasNext()) {
FileItemStream item = iter.next();
String name = item.getFieldName();
InputStream stream = item.openStream();
if (item.isFormField()) {
System.out.println("Form field " + name + " with value "
+ Streams.asString(stream) + " detected.");
} else {
System.out.println("File field " + name + " with file name "
+ item.getName() + " detected.");
//loads only the first file
if(bytes.length==0)
bytes = IOUtils.toByteArray(item.openStream());
}
}
} catch (FileUploadException e) {
e.printStackTrace();
}
} else {
response.getWriter().print("is not a multipart request");
response.setStatus(200);
}
response.getWriter().print("bytes uploaded in file" + bytes.length);
//TODO store in session etc...
}
}
如何在 Java 中不使用临时文件直接将文件上传到 HTTP 服务器内存? 我目前在 tomcat 上使用 Struts 2 和 apache ServletFileUpload,但我还没有找到实现此目的的方法。
在 apache 中,class FileUploadBase parseRequest(RequestContext ctx)... 正在创建临时文件
public List<FileItem> parseRequest(RequestContext ctx)
...
Streams.copy(item.openStream(), fileItem.getOutputStream(), true);
基于此文档 here 我编写了以下 servlet 以在不创建临时文件的情况下上传到字节数组。
import java.io.IOException;
import java.io.InputStream;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import org.apache.commons.fileupload.FileItemIterator;
import org.apache.commons.fileupload.FileItemStream;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.fileupload.util.Streams;
import org.apache.commons.io.IOUtils;
@WebServlet("/upload")
public class UploadByteArrayServlet extends HttpServlet {
private static final long serialVersionUID = 1123445L;
private static final int MAX_FILE_SIZE = 1024 * 1024 * 1; // 1MB
private static final int MAX_REQUEST_SIZE = 1024 * 1024 * 1; // 1MB
protected void doPost(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
byte[] bytes = "".getBytes();
boolean isMultipart = ServletFileUpload.isMultipartContent(request);
if(isMultipart){
ServletFileUpload upload = new ServletFileUpload();
upload.setFileSizeMax(MAX_FILE_SIZE);
upload.setSizeMax(MAX_REQUEST_SIZE);
try {
// Parse the request
FileItemIterator iter = upload.getItemIterator(request);
while (iter.hasNext()) {
FileItemStream item = iter.next();
String name = item.getFieldName();
InputStream stream = item.openStream();
if (item.isFormField()) {
System.out.println("Form field " + name + " with value "
+ Streams.asString(stream) + " detected.");
} else {
System.out.println("File field " + name + " with file name "
+ item.getName() + " detected.");
//loads only the first file
if(bytes.length==0)
bytes = IOUtils.toByteArray(item.openStream());
}
}
} catch (FileUploadException e) {
e.printStackTrace();
}
} else {
response.getWriter().print("is not a multipart request");
response.setStatus(200);
}
response.getWriter().print("bytes uploaded in file" + bytes.length);
//TODO store in session etc...
}
}