Algolia 按子键值过滤

Question

我有一组数据：

{
  "creatorUsername": "mbalex99",
  "description": "For Hikers and All the Lovers Alike!",
  "imageUrl": "https://s3.amazonaws.com/edenmessenger/uploads/28C03B77-E3E9-4D33-A433-6522C0480C16.jpg",
  "isPrivate": true,
  "name": "Nature Lovers ",
  "roomId": "-KILq0nBN8wHQuEjMYRF",
  "usernames": {
    "bannon": true,
    "loveless": true,
    "mbalex99": true,
    "terra": true
  },
  "objectID": "-KILq0nBN8wHQuEjMYRF"
}

我似乎找不到 usernames 其中键等于 mbalex99?

Answer 1

Algolia 确实做不到这一点。您只能按值过滤。
但是，您绝对可以添加一个包含对象键的数组并按此属性进行过滤：

"usernames": {
  "bannon": true,
  "loveless": true,
  "mbalex99": true,
  "terra": true
},
"usernameList": ["bannon", "loveless", "mbalex99", "terra"]
// ...

和

// At query time:
{ "facetFilters": "usernameList:mbalex99" }

Algolia 按子键值过滤

Algolia filter by sub key value

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