我正在阅读 post,有人的评论让我感到困惑。
I was reading a post and someones comment confused me.
好的,所以我在 java 中查找 goto 语句,我偶然发现了这个 post:
Is there a goto statement in Java?
(我知道,我是磨砂膏 :P )
无论如何,我在评论中偶然发现了这段代码:
public static void main(String [] args) {
boolean t = true;
first:
{
second:
{
third:
{
System.out.println("Before the break");
if (t) {
break second;
}
System.out.println("Not executed");
}
System.out.println("Not executed - end of second block");
}
System.out.println("End of third block");
}
}
我很困惑为什么第二个块在休息后没有被执行。有人可以给我解释一下吗?
我本来想问的,但我没有足够高的代表来这样做。
谢谢!
And I am confused as to why the second block wouldn't have been
executed after the break.
因为带标签的break
语句终止了带标签的块,并没有将执行带回标签。
好的,所以我在 java 中查找 goto 语句,我偶然发现了这个 post: Is there a goto statement in Java? (我知道,我是磨砂膏 :P )
无论如何,我在评论中偶然发现了这段代码:
public static void main(String [] args) {
boolean t = true;
first:
{
second:
{
third:
{
System.out.println("Before the break");
if (t) {
break second;
}
System.out.println("Not executed");
}
System.out.println("Not executed - end of second block");
}
System.out.println("End of third block");
}
}
我很困惑为什么第二个块在休息后没有被执行。有人可以给我解释一下吗?
我本来想问的,但我没有足够高的代表来这样做。
谢谢!
And I am confused as to why the second block wouldn't have been executed after the break.
因为带标签的break
语句终止了带标签的块,并没有将执行带回标签。