如何根据 Laravel 中的 ID 匹配从 3 个不同的表中获得最佳结果。

Question

正在尝试获取特定供应商的产品和变体。我可以很容易地获得产品，但无法弄清楚如何最好地获得匹配 product_id 的变体并将其发送到视图。 Variants.product_id 匹配 Product.ID

这有效（为供应商获取产品）

 public function suppliers($id) {

    $supplier = Supplier::orderby('company_name', 'ASC')->find($id);
    $products = Supplier::find($id)->products;

    $data = [];
    $data['supplier'] = $supplier;
    $data['products'] = $products;

    return view('admin.purchasing.supplier-details', $data);
}

我已经试过这个来获得变体，但没有成功。

控制器：

    public function suppliers($id) {

    $supplier = Supplier::orderby('company_name', 'ASC')->find($id);
    $products = Supplier::find($id)->products;
    $variants = array();
    foreach ($products as $product) {
        $product_id = $product->id;
        $variants[] = Variant::find($product_id);
    }
    $data = [];
    $data['supplier'] = $supplier;
    $data['products'] = $products;
    $data['variants'] = $variants;
    return view('admin.purchasing.supplier-details', $data);
}

查看：

    @foreach($products as $product)
        <tr>
            <td>{{ $product['title'] }}</td>
            @foreach($variants as $variant)
                @if($variant->product_id == $product['id'])
                    <td>${{ $variant->price }}</td>   
                @else
                    <td>not set</td>
                @endif
            @endforeach    
        </tr>
    @endforeach

非常感谢任何提示。

Answer 1

首先，你应该在你的模型上设置关系才能完成这项工作

像这样例如：

Supplier.php

public function products()
{
    return $this->hasMany('App\Product');
}

Product.php

 public function variants()
{
    return $this->hasMany('App\Variant');
}
public function Supplier()
{
    return $this->belongsToMany('App\Supplier'); //in case you have only one supplier for each product change this to belongsto
}

Variant.php

public function products()
    {
        return $this->belongsToMany('App\Product'); //not sure if this should be manytomany or one to many , it deppends on what you did
    }

无论如何现在你可以做到这一点

控制器

public function suppliers($id) {

    $Data = Supplier::where('id',$id)->orderby('company_name', 'ASC')->with('products.variants')->first(); //you will get the supplier with all products associated to him with variants foreach product

    return view('admin.purchasing.supplier-details')->with('Data',$Data); // now you just loop the $supplierwithproducts->products to get results (dd the variable to check output)

    }

查看

{{ $Data->name }} // supplier name since Supplier model was the starting point
@foreach($Data->products as $product) //loop all products related to that supplier
  {{ $product->name }} //shows product name (depends on you database columns
    @foreach($product->variants as $variant) // loops all variants in the current product
      {{ $variant->name }} // shows variants
    @endforeach
@endforeach

如果您复制并粘贴此代码，它可能无法正常工作，但这会让您了解应该如何处理 laravel 中的关系（levrage eloquent 关系）

查看此以获取更多信息

Laravel Docs

Laracasts Defining Relationships With Eloquent

Laracasts Updating Records and Eager Loading

如何根据 Laravel 中的 ID 匹配从 3 个不同的表中获得最佳结果。

How to best get results from 3 different tables based on ID matches in Laravel.

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