减去涉及多个连接的日期
Subtracting Dates with multiple Joins Involved
我希望有人能帮助我。
我有以下 5 个表：
tblCustomer
CustomerID CustomerName
------- ------------
1 ABC Bank
2 Chase Bank
tblOrderType
OrderTypeID OrderTypeName
---------- ------------
1 Assignment
2 LienRelease
tblActivity
ActivityID ActivityName
---------- ------------
1 Received
2 Keyed
3 Printed
4 Delivered To Customer
tblOrder
OrderID CustomerID OrderTypeID LoanNumber
---------- ------------ ----------- ----------
1 1 1 45584565
2 1 1 45566856
3 1 1 45565584
4 1 1 45588545
tblOrderActivity
OrderID ActivityID ActivityDate
---------- ----------- ----------
1 1 2007-04-16 8:34:00 AM
1 2 2007-04-16 9:22:00 AM
1 3 2007-04-16 9:51:00 AM
1 4 2007-04-16 4:14:00 PM
2 1 2007-04-16 8:34:00 AM
2 3 2014-12-16 10:33:09 AM
3 1 2007-04-16 8:34:00 AM
3 2 2007-04-16 9:22:00 AM
3 3 2007-04-16 9:51:00 AM
3 4 2007-04-16 4:14:00 PM
4 1 2007-04-16 8:34:00 AM
4 2 2007-04-16 9:22:00 AM
4 3 2007-04-16 9:51:00 AM
出于保护目的，信息已更改。所以说我需要能够列出客户的所有订单和时差（以分钟为单位）：
-“接收”到“键控”为 [TurnTime1]
-“键入”到“打印”为 [TurnTime2]
-“打印”到“交付”为 [TurnTime3]
-“已接收”到“已交付”为 [TurnTime4]
我还需要 return CustomerName、OrderTypeName、LoanNumber、TurnTime1、TurnTime2、TurnTime3 和 TurnTime4。我相信我很接近，但是，我尝试了两种不同的方法来做到这一点，这两种方法都不正确，我被卡住了。第一个选项仅包含 4 行，每个 TurnTime 列的值为“0”。第二个选项包括 600 多行。我相信这应该是 return 只有 11 行数据和一些数据不符合规定的额外行。这是我目前所拥有的：
选项 1
SELECT DISTINCT tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblOrder.LoanNumber,
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime1],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime2],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime3],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime4]
FROM tblOrder
INNER JOIN tblOrderActivity
ON tblOrder.OrderID = tblOrderActivity.OrderID
INNER JOIN tblActivity
ON tblOrderActivity.ActivityID = tblActivity.ActivityID
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
WHERE EXISTS (SELECT * FROM tblActivity WHERE ActivityName IS NOT NULL)
GROUP BY tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblorder.LoanNumber, tblOrderActivity.ActivityDate;
选项 2
SELECT DISTINCT tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblOrder.LoanNumber,
(DATEPART(mi,(TT2.ActivityDate - TT1.ActivityDate))) AS [TurnTime1],
(DATEPART(mi,(TT3.ActivityDate - TT2.ActivityDate))) AS [TurnTime2],
(DATEPART(mi,(TT4.ActivityDate - TT3.ActivityDate))) AS [TurnTime3],
(DATEPART(mi,(TT4.ActivityDate - TT1.ActivityDate))) AS [TurnTime4]
FROM tblOrder
INNER JOIN tblOrderActivity AS TT1
ON tblOrder.OrderID = TT1.OrderID
INNER JOIN tblOrderActivity AS TT2
ON tblOrder.OrderID = TT2.OrderID
INNER JOIN tblOrderActivity AS TT3
ON tblOrder.OrderID = TT3.OrderID
INNER JOIN tblOrderActivity AS TT4
ON tblOrder.OrderID = TT4.OrderID
INNER JOIN tblActivity AS TA1
ON TT1.ActivityID = TA1.ActivityID
INNER JOIN tblActivity AS TA2
ON TT2.ActivityID = TA2.ActivityID
INNER JOIN tblActivity AS TA3
ON TT3.ActivityID = TA3.ActivityID
INNER JOIN tblActivity AS TA4
ON TT4.ActivityID = TA4.ActivityID
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
WHERE EXISTS (SELECT * FROM tblActivity WHERE ActivityName IS NOT NULL)
GROUP BY tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblorder.LoanNumber, TT1.ActivityDate,
TT2.ActivityDate, TT3.ActivityDate, TT4.ActivityDate;
您可以使用 case based aggregation 和减法来计算客户每个订单的活动之间的时间差。
select C.CustomerNAme, OT.OrderTypeName, O.LoanNumber,
max ( case when OA.ActivityID =2 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =1 then datediff(minute,0,OA.ActivityDate) end) as TurnTime1,
max ( case when OA.ActivityID =3 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =2 then datediff(minute,0,OA.ActivityDate) end) as TurnTime2,
max ( case when OA.ActivityID =4 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =3 then datediff(minute,0,OA.ActivityDate) end) as TurnTime3,
max ( case when OA.ActivityID =4 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =1 then datediff(minute,0,OA.ActivityDate) end) as TurnTime4
FROM tblCustomer C
JOIN tblOrder O
on C.CustomerID = O.CustomerID
JOIN tblOrderActivity OA
on OA.OrderID = O.OrderID
JOIN tblOrderType OT
on OT.OrderTypeID = O.OrderTypeID
GROUP BY C.CustomerName, OT.OrderTypeName, O.LoanNumber
这应该只是一个简单的问题，即根据 table activity 为您想要的每个组创建一个连接 table。请注意，尽管我假设 activity 只能执行一次。
Select tblCustomer.CustomerName,
tblOrderType.OrderTypeName,
tblOrder.LoanNumber,
DATEDiff(mi,tblOrderReceived.ActivityDate, tblOrderKeyed.ActivityDate) AS [TurnTime1],
DATEDiff(mi,tblOrderKeyed.ActivityDate, tblOrderPrinted.ActivityDate) AS [TurnTime2],
DATEDiff(mi,tblOrderPrinted.ActivityDate, tblOrderDelivered.ActivityDate) AS [TurnTime3],
DATEDiff(mi,tblOrderReceived.ActivityDate, tblOrderDelivered.ActivityDate) AS [TurnTime4]
From tblOrder
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
Left Outer Join tblOrderActivity tblOrderReceived
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderKeyed
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderPrinted
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderDelivered
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblActivity
ON tblOrderReceived.ActivityID = tblActivity.ActivityID
OR tblOrderKeyed.ActivityID = tblActivity.ActivityID
OR tblOrderPrinted.ActivityID = tblActivity.ActivityID
OR tblOrderDelivered.ActivityID = tblActivity.ActivityID
Where tblOrderReceived.ActivityID = 1
And tblOrderKeyed.ActivityID = 2
And tblOrderPrinted.ActivityID = 3
And tblOrderDelivered.ActivityID = 4
And tblOrder.OrderID In (Select ActivityMask.OrderID from tblOrderActivity ActivityMask)
这个怎么样：
SQL Fiddle
MS SQL Server 2008 架构设置:
create table tblCustomer
(
CustomerID int,
CustomerName varchar(max)
)
INSERT INTO tblCustomer
VALUES
( 1, 'ABC Bank'),
( 2, 'Chase Bank')
create table tblOrderType
(
OrderTypeID int,
OrderTypeName varchar(max)
)
INSERT INTO tblOrderType
VALUES
( 1, 'Assignment'),
( 2, 'LienRelease')
create table tblActivity
(
ActivityID int,
ActivityName varchar(max)
)
INSERT INTO tblActivity
VALUES
( 1, 'Received'),
( 2, 'Keyed'),
( 3, 'Printed'),
( 4, 'Delivered To Customer')
CREATE TABLE tblOrder
(
OrderID int,
CustomerID int,
OrderTypeID int,
LoanNumber int
)
INSERT INTO tblOrder
VALUES
( 1, 1, 1, 45584565),
( 2, 1, 1, 45566856),
( 3, 1, 1, 45565584),
( 4, 1, 1, 45588545)
CREATE TABLE tblOrderActivity
(
OrderID int,
ActivityID int,
ActivityDate DateTime
)
INSERT INTO tblOrderActivity
VALUES
(1, 1, '2007-04-16 8:34:00 AM'),
(1, 2, '2007-04-16 9:22:00 AM'),
(1, 3, '2007-04-16 9:51:00 AM'),
(1, 4, '2007-04-16 4:14:00 PM'),
(2, 1, '2007-04-16 8:34:00 AM'),
(2, 3, '2014-12-16 10:33:09 AM'),
(3, 1, '2007-04-16 8:34:00 AM'),
(3, 2, '2007-04-16 9:22:00 AM'),
(3, 3, '2007-04-16 9:51:00 AM'),
(3, 4, '2007-04-16 4:14:00 PM'),
(4, 1, '2007-04-16 8:34:00 AM'),
(4, 2, '2007-04-16 9:22:00 AM'),
(4, 3, '2007-04-16 9:51:00 AM')
查询 1:
SELECT C.CustomerName,O.OrderId, OT.OrderTypeName, O.LoanNumber,
(DATEDIFF(mi, Received.ActivityDate, Keyed.ActivityDate)) AS [TurnTime1],
(DATEDIFF(mi, Keyed.ActivityDate, Printed.ActivityDate)) AS [TurnTime2],
(DATEDIFF(mi, Printed.ActivityDate, Delivered.ActivityDate)) AS [TurnTime3],
(DATEDIFF(mi, Received.ActivityDate, Delivered.ActivityDate)) AS [TurnTime4]
FROM tblCustomer C
INNER JOIN tblOrder O
ON O.CustomerId = C.CustomerId
INNER JOIN tblOrderType OT
ON OT.OrderTypeID = O.OrderTypeID
INNER JOIN tblOrderActivity Received
ON Received.OrderID = O.OrderID AND Received.ActivityId = 1
LEFT JOIN tblOrderActivity Keyed
ON Keyed.OrderID = O.OrderID AND Keyed.ActivityId = 2
LEFT JOIN tblOrderActivity Printed
ON Printed.OrderID = O.OrderID AND Printed.ActivityId = 3
LEFT JOIN tblOrderActivity Delivered
ON Delivered.OrderID = O.OrderID AND Delivered.ActivityId = 4
| CUSTOMERNAME | ORDERID | ORDERTYPENAME | LOANNUMBER | TURNTIME1 | TURNTIME2 | TURNTIME3 | TURNTIME4 |
|--------------|---------|---------------|------------|-----------|-----------|-----------|-----------|
| ABC Bank | 1 | Assignment | 45584565 | 48 | 29 | 383 | 460 |
| ABC Bank | 2 | Assignment | 45566856 | (null) | (null) | (null) | (null) |
| ABC Bank | 3 | Assignment | 45565584 | 48 | 29 | 383 | 460 |
| ABC Bank | 4 | Assignment | 45588545 | 48 | 29 | (null) | (null) |
如需剔除NULL行，只需将LEFT JOIN改为INNER JOIN
即可
我希望有人能帮助我。
我有以下 5 个表：
tblCustomer
CustomerID CustomerName
------- ------------
1 ABC Bank
2 Chase Bank
tblOrderType
OrderTypeID OrderTypeName
---------- ------------
1 Assignment
2 LienRelease
tblActivity
ActivityID ActivityName
---------- ------------
1 Received
2 Keyed
3 Printed
4 Delivered To Customer
tblOrder
OrderID CustomerID OrderTypeID LoanNumber
---------- ------------ ----------- ----------
1 1 1 45584565
2 1 1 45566856
3 1 1 45565584
4 1 1 45588545
tblOrderActivity
OrderID ActivityID ActivityDate
---------- ----------- ----------
1 1 2007-04-16 8:34:00 AM
1 2 2007-04-16 9:22:00 AM
1 3 2007-04-16 9:51:00 AM
1 4 2007-04-16 4:14:00 PM
2 1 2007-04-16 8:34:00 AM
2 3 2014-12-16 10:33:09 AM
3 1 2007-04-16 8:34:00 AM
3 2 2007-04-16 9:22:00 AM
3 3 2007-04-16 9:51:00 AM
3 4 2007-04-16 4:14:00 PM
4 1 2007-04-16 8:34:00 AM
4 2 2007-04-16 9:22:00 AM
4 3 2007-04-16 9:51:00 AM
出于保护目的，信息已更改。所以说我需要能够列出客户的所有订单和时差（以分钟为单位）： -“接收”到“键控”为 [TurnTime1] -“键入”到“打印”为 [TurnTime2] -“打印”到“交付”为 [TurnTime3] -“已接收”到“已交付”为 [TurnTime4] 我还需要 return CustomerName、OrderTypeName、LoanNumber、TurnTime1、TurnTime2、TurnTime3 和 TurnTime4。我相信我很接近，但是，我尝试了两种不同的方法来做到这一点，这两种方法都不正确，我被卡住了。第一个选项仅包含 4 行，每个 TurnTime 列的值为“0”。第二个选项包括 600 多行。我相信这应该是 return 只有 11 行数据和一些数据不符合规定的额外行。这是我目前所拥有的：
选项 1
SELECT DISTINCT tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblOrder.LoanNumber,
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime1],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime2],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime3],
(DATEPART(mi,(tblOrderActivity.ActivityDate - tblOrderActivity.ActivityDate))) AS [TurnTime4]
FROM tblOrder
INNER JOIN tblOrderActivity
ON tblOrder.OrderID = tblOrderActivity.OrderID
INNER JOIN tblActivity
ON tblOrderActivity.ActivityID = tblActivity.ActivityID
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
WHERE EXISTS (SELECT * FROM tblActivity WHERE ActivityName IS NOT NULL)
GROUP BY tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblorder.LoanNumber, tblOrderActivity.ActivityDate;
选项 2
SELECT DISTINCT tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblOrder.LoanNumber,
(DATEPART(mi,(TT2.ActivityDate - TT1.ActivityDate))) AS [TurnTime1],
(DATEPART(mi,(TT3.ActivityDate - TT2.ActivityDate))) AS [TurnTime2],
(DATEPART(mi,(TT4.ActivityDate - TT3.ActivityDate))) AS [TurnTime3],
(DATEPART(mi,(TT4.ActivityDate - TT1.ActivityDate))) AS [TurnTime4]
FROM tblOrder
INNER JOIN tblOrderActivity AS TT1
ON tblOrder.OrderID = TT1.OrderID
INNER JOIN tblOrderActivity AS TT2
ON tblOrder.OrderID = TT2.OrderID
INNER JOIN tblOrderActivity AS TT3
ON tblOrder.OrderID = TT3.OrderID
INNER JOIN tblOrderActivity AS TT4
ON tblOrder.OrderID = TT4.OrderID
INNER JOIN tblActivity AS TA1
ON TT1.ActivityID = TA1.ActivityID
INNER JOIN tblActivity AS TA2
ON TT2.ActivityID = TA2.ActivityID
INNER JOIN tblActivity AS TA3
ON TT3.ActivityID = TA3.ActivityID
INNER JOIN tblActivity AS TA4
ON TT4.ActivityID = TA4.ActivityID
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
WHERE EXISTS (SELECT * FROM tblActivity WHERE ActivityName IS NOT NULL)
GROUP BY tblCustomer.CustomerName, tblOrderType.OrderTypeName, tblorder.LoanNumber, TT1.ActivityDate,
TT2.ActivityDate, TT3.ActivityDate, TT4.ActivityDate;
您可以使用 case based aggregation 和减法来计算客户每个订单的活动之间的时间差。
select C.CustomerNAme, OT.OrderTypeName, O.LoanNumber,
max ( case when OA.ActivityID =2 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =1 then datediff(minute,0,OA.ActivityDate) end) as TurnTime1,
max ( case when OA.ActivityID =3 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =2 then datediff(minute,0,OA.ActivityDate) end) as TurnTime2,
max ( case when OA.ActivityID =4 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =3 then datediff(minute,0,OA.ActivityDate) end) as TurnTime3,
max ( case when OA.ActivityID =4 then datediff(minute,0,OA.ActivityDate) end) -
max ( case When OA.ActivityID =1 then datediff(minute,0,OA.ActivityDate) end) as TurnTime4
FROM tblCustomer C
JOIN tblOrder O
on C.CustomerID = O.CustomerID
JOIN tblOrderActivity OA
on OA.OrderID = O.OrderID
JOIN tblOrderType OT
on OT.OrderTypeID = O.OrderTypeID
GROUP BY C.CustomerName, OT.OrderTypeName, O.LoanNumber
这应该只是一个简单的问题，即根据 table activity 为您想要的每个组创建一个连接 table。请注意，尽管我假设 activity 只能执行一次。
Select tblCustomer.CustomerName,
tblOrderType.OrderTypeName,
tblOrder.LoanNumber,
DATEDiff(mi,tblOrderReceived.ActivityDate, tblOrderKeyed.ActivityDate) AS [TurnTime1],
DATEDiff(mi,tblOrderKeyed.ActivityDate, tblOrderPrinted.ActivityDate) AS [TurnTime2],
DATEDiff(mi,tblOrderPrinted.ActivityDate, tblOrderDelivered.ActivityDate) AS [TurnTime3],
DATEDiff(mi,tblOrderReceived.ActivityDate, tblOrderDelivered.ActivityDate) AS [TurnTime4]
From tblOrder
INNER JOIN tblOrderType
ON tblOrderType.OrderTypeID = tblOrder.OrderTypeID
INNER JOIN tblCustomer
ON tblCustomer.CustomerID = tblOrder.CustomerID
Left Outer Join tblOrderActivity tblOrderReceived
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderKeyed
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderPrinted
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblOrderActivity tblOrderDelivered
ON tblOrder.OrderID = tblOrderActivity.OrderID
Left Outer Join tblActivity
ON tblOrderReceived.ActivityID = tblActivity.ActivityID
OR tblOrderKeyed.ActivityID = tblActivity.ActivityID
OR tblOrderPrinted.ActivityID = tblActivity.ActivityID
OR tblOrderDelivered.ActivityID = tblActivity.ActivityID
Where tblOrderReceived.ActivityID = 1
And tblOrderKeyed.ActivityID = 2
And tblOrderPrinted.ActivityID = 3
And tblOrderDelivered.ActivityID = 4
And tblOrder.OrderID In (Select ActivityMask.OrderID from tblOrderActivity ActivityMask)
这个怎么样： SQL Fiddle
MS SQL Server 2008 架构设置:
create table tblCustomer
(
CustomerID int,
CustomerName varchar(max)
)
INSERT INTO tblCustomer
VALUES
( 1, 'ABC Bank'),
( 2, 'Chase Bank')
create table tblOrderType
(
OrderTypeID int,
OrderTypeName varchar(max)
)
INSERT INTO tblOrderType
VALUES
( 1, 'Assignment'),
( 2, 'LienRelease')
create table tblActivity
(
ActivityID int,
ActivityName varchar(max)
)
INSERT INTO tblActivity
VALUES
( 1, 'Received'),
( 2, 'Keyed'),
( 3, 'Printed'),
( 4, 'Delivered To Customer')
CREATE TABLE tblOrder
(
OrderID int,
CustomerID int,
OrderTypeID int,
LoanNumber int
)
INSERT INTO tblOrder
VALUES
( 1, 1, 1, 45584565),
( 2, 1, 1, 45566856),
( 3, 1, 1, 45565584),
( 4, 1, 1, 45588545)
CREATE TABLE tblOrderActivity
(
OrderID int,
ActivityID int,
ActivityDate DateTime
)
INSERT INTO tblOrderActivity
VALUES
(1, 1, '2007-04-16 8:34:00 AM'),
(1, 2, '2007-04-16 9:22:00 AM'),
(1, 3, '2007-04-16 9:51:00 AM'),
(1, 4, '2007-04-16 4:14:00 PM'),
(2, 1, '2007-04-16 8:34:00 AM'),
(2, 3, '2014-12-16 10:33:09 AM'),
(3, 1, '2007-04-16 8:34:00 AM'),
(3, 2, '2007-04-16 9:22:00 AM'),
(3, 3, '2007-04-16 9:51:00 AM'),
(3, 4, '2007-04-16 4:14:00 PM'),
(4, 1, '2007-04-16 8:34:00 AM'),
(4, 2, '2007-04-16 9:22:00 AM'),
(4, 3, '2007-04-16 9:51:00 AM')
查询 1:
SELECT C.CustomerName,O.OrderId, OT.OrderTypeName, O.LoanNumber,
(DATEDIFF(mi, Received.ActivityDate, Keyed.ActivityDate)) AS [TurnTime1],
(DATEDIFF(mi, Keyed.ActivityDate, Printed.ActivityDate)) AS [TurnTime2],
(DATEDIFF(mi, Printed.ActivityDate, Delivered.ActivityDate)) AS [TurnTime3],
(DATEDIFF(mi, Received.ActivityDate, Delivered.ActivityDate)) AS [TurnTime4]
FROM tblCustomer C
INNER JOIN tblOrder O
ON O.CustomerId = C.CustomerId
INNER JOIN tblOrderType OT
ON OT.OrderTypeID = O.OrderTypeID
INNER JOIN tblOrderActivity Received
ON Received.OrderID = O.OrderID AND Received.ActivityId = 1
LEFT JOIN tblOrderActivity Keyed
ON Keyed.OrderID = O.OrderID AND Keyed.ActivityId = 2
LEFT JOIN tblOrderActivity Printed
ON Printed.OrderID = O.OrderID AND Printed.ActivityId = 3
LEFT JOIN tblOrderActivity Delivered
ON Delivered.OrderID = O.OrderID AND Delivered.ActivityId = 4
| CUSTOMERNAME | ORDERID | ORDERTYPENAME | LOANNUMBER | TURNTIME1 | TURNTIME2 | TURNTIME3 | TURNTIME4 |
|--------------|---------|---------------|------------|-----------|-----------|-----------|-----------|
| ABC Bank | 1 | Assignment | 45584565 | 48 | 29 | 383 | 460 |
| ABC Bank | 2 | Assignment | 45566856 | (null) | (null) | (null) | (null) |
| ABC Bank | 3 | Assignment | 45565584 | 48 | 29 | 383 | 460 |
| ABC Bank | 4 | Assignment | 45588545 | 48 | 29 | (null) | (null) |
如需剔除NULL行，只需将LEFT JOIN改为INNER JOIN