存储过程超时

Question

正在尝试收集一些分层数据以发送给第三方，并被定向到 this post。

尝试将其调整到我在 SQL Fiddle 上的用例后，存储过程一直超时。
所以我在本地尝试了两次（通过 PhpMyAdmin）。
当我在调用存储过程后尝试在浏览器中重新加载 PMA 时，我只得到一个永恒的 "waiting for response" 微调器（超过 10 或 20 分钟）。

我假设我的 SP 代码有问题？？？

CREATE TABLE foo
    (`id` int, `name` varchar(100), `parentId` int, `path` varchar(100))
//

INSERT INTO foo (`id`, `name`, `parentId`, `path`)
VALUES (1, 'discrete', 0, NULL),
       (2, 'res', 1, NULL),
       (3, 'smt', 2, NULL),
       (4, 'cap', 1, NULL),
       (5, 'ind', 1, NULL),
       (6, 'smt', 4, NULL),
       (7, 'tant', 6, NULL),
       (8, 'cer', 6, NULL)
//

CREATE PROCEDURE updatePath()
BEGIN
DECLARE cnt, n int;
    SELECT COUNT(*) INTO n FROM foo WHERE parentId = 0;
    UPDATE foo a, foo b SET a.path = b.name WHERE b.parentId IS NULL AND a.parentId = b.id;
    SELECT count(*) INTO cnt FROM foo WHERE path IS NULL;
    while cnt > n do
        UPDATE foo a, foo b SET a.path = concat(b.path, '|', b.id) WHERE b.path IS NOT NULL AND a.parentId = b.id;
        SELECT count(*) INTO  cnt FROM foo WHERE path IS NULL;
    end while;
END//

编辑
预期结果：

VALUES (1, 'discrete', 0, '1'),
       (2, 'res', 1, '1|2'),
       (3, 'smt', 2, '1|2|3'),
       (4, 'cap', 1, '1|4'),
       (5, 'ind', 1, '1|5'),
       (6, 'smt', 4, '1|4|6'),
       (7, 'tant', 6, '1|4|6|7'),
       (8, 'cer', 6, '1|4|6|8');

Answer 1

您是否正在尝试进行 self-referencing 连接以创建层次结构？

select a.name, 父母姓名 = b.name 从富一个，外连接 foo b on ( a.id = b.parentId )

Answer 2

睡了一夜好觉后，我在@Drew 的带领下，一次检查了一台电脑。
得到它的工作。这是我要离开的地方：

CREATE TABLE foo
    (`id` int, `name` varchar(100), `parentId` int, `path` varchar(100))
//

INSERT INTO foo
    (`id`, `name`, `parentId`, `path`)
VALUES
    (1, 'dscr', 0, NULL),
    (2, 'res', 1, NULL),
    (3, 'smt', 2, NULL),
    (4, 'cap', 1, NULL),
    (5, 'ind', 1, NULL),
    (6, 'chp', 4, NULL),
    (7, 'tant', 6, NULL),
    (8, 'cer', 6, NULL)
//

CREATE PROCEDURE updatePath()
BEGIN
DECLARE cnt, n int;

    SELECT COUNT(*) INTO n FROM foo WHERE parentId = 0; -- n is now 1
    SELECT COUNT(*) INTO cnt FROM foo WHERE path IS NULL; -- cnt is now 8

    UPDATE foo child, foo parent        -- each child now has its parent and own ID's in the path
      SET child.path = CONCAT(parent.id, '|', child.id)
      WHERE parent.parentId = 0
      AND child.parentId = parent.id;

    WHILE cnt > n DO
        UPDATE foo child, foo parent    -- concat parent's path and own ID into each empty child's path
          SET child.path = concat( parent.path,'|',child.id ) 
          WHERE parent.path IS NOT NULL 
          AND child.parentId = parent.id;

        SELECT COUNT(*) INTO  cnt  -- decrement cnt
          FROM foo 
          WHERE path IS NULL;

    END WHILE;

    UPDATE foo  -- set path for any top-level categories
      SET path = id
      WHERE path IS NULL;

END//

call updatePath()//

欢迎批评。
希望这对其他人有帮助。

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