post_save.disconnect 根本不起作用

Question

我试图让 Django 在一种情况下不发送信号。添加模型 Delivery 的新实例（在创建 Job 之后）作为模型 Job 的属性时，我不想发送信号，因为信号应该提醒管理员 Job 已被编辑。

不幸的是，我做不到。

@receiver(post_save,sender=Job) # When Job is created or edited
def alert_admin(sender,instance,created,**kwargs):
    if created:
        email.AdminNotifications.new_order(instance)
    else:
        email.AdminNotifications.edited_order(instance)

@receiver(post_save,sender=Job) # When job is created, I want to create a delivery object as an attribute of Job
def create_delivery(sender,instance,created,**kwargs):
    if created:
        delivery,created_delivery = Delivery.objects.get_or_create(job=instance)
        instance.delivery = delivery
        delivery.save()
        post_save.disconnect(alert_admin)
        instance.save() # I DONT WANT TO SEND SIGNAL IN THIS CASE
        post_save.connect(alert_admin)

问题出在哪里？我这样做了，但我仍然收到两个警报 - New Order 和 Edited Order.

Answer 1

问题是您正在收听同一个信号两次。

@receiver(post_save,sender=Job) # When Job is created or edited
def alert_admin(sender,instance,created,**kwargs):
    ###

@receiver(post_save,sender=Job):
def create_delivery(sender,instance,created,**kwargs):
   ###

您保证 create_delivery 将首先被调用。但这似乎并没有发生。 alert_admin 似乎最先被调用。因此，您在 create_delivery 中所做的任何禁用信号都只是浪费。

Django 不对触发信号的顺序提供任何保证或控制 (what's the order of post_save receiver in django?)

您可以向您的实例添加一个简单的标志，以告知信号处理器该信号不需要进一步处理。

if hasattr(instance,'signal_processed'):
     return
else:
    # do whatever processing
    instance.signal_processed = True

post_save.disconnect 根本不起作用

post_save.disconnect does not work at all

python

django

django-models

django-signals