在 class 的地方爆炸

Question

我在 "select" 语句中使用数组时遇到问题该数组包含以下字符串大批 ( [0] => M.A.JINNA [1] => K.DHANA 拉朱 [2] => B.EPHRIM ) 数组数据来自以下数据

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" 
"http://www.w3.org/TR/html4/loose.dtd">
<html>
<style>
table{
 border : 1px solid black;
}
tr{
 border : 1px solid black;
}
td{
 border : 1px solid black;
}
</style

<head>
<meta http-equiv="X-UA-Compatible" content="IE=EmulateIE8">
<meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1">
<title>Update Deployement</title>

<style type="text/css">
body
{
   background-color: #00FF00;
   background-image: url(images/gail-india.jpg);
   color: #000000;
   scrollbar-face-color: #0B0B0B;
   scrollbar-arrow-color: #C8C8C8;
   scrollbar-3dlight-color: #0B0B0B;
   scrollbar-darkshadow-color: #000000;
   scrollbar-highlight-color: #141414;
   scrollbar-shadow-color: #060606;
   scrollbar-track-color: #0B0B0B;
}
</style>
</head>


<body>
<form method="post" action="edit_data.php">
<div id="wb_Image3" style="margin:0;padding:0;position:absolute;left:7px;top:4px;width:208px;height:129px;text-align:left;z-index:0;">
<img src="images/image_thumb3.png" id="Image2" alt="" border="0" style="width:208px;height:129px;"></div>

<?php
$con = mysql_connect("localhost","root","");
 if (!$con)
{
  die('Could not connect: ' . mysql_error());
}
mysql_select_db("gail", $con);
$installation_1 = trim($_POST['installation']);
$area_1 = trim($_POST['area']);
$district_1 = trim($_POST['district']);

if(empty($area_1) AND empty($district_1))
{
$sql = "SELECT * FROM deployment WHERE installation ='" . $installation_1 . "'";
}

else if(empty($installation_1) AND empty($district_1))
{
$sql = "SELECT * FROM deployment WHERE area ='" . $area_1 . "'";
}

else if(empty($installation_1) AND empty($area_1))
{
$sql = "SELECT * FROM deployment WHERE district ='" . $district_1 . "'";
}

else if(empty($district_1))
{
$sql = "SELECT * FROM deployment WHERE installation ='" . $installation_1 . "' AND area ='" . $area_1 . "'";
}

else if(empty($area_1))
{
$sql = "SELECT * FROM deployment WHERE installation ='" . $installation_1 . "' AND district ='" . $district_1 . "'";
}


else if(empty($installation_1))
{
$sql = "SELECT * FROM deployment WHERE area ='" . $area_1 . "' AND district ='" . $district_1 . "'";
}

else
{
$sql = "SELECT * FROM deployment WHERE installation ='" . $installation_1 . "' AND area ='" . $area_1 . "' AND district ='" . $district_1 . "'";
}
$result = mysql_query($sql);

echo "<table id='table1' width = '500' align = 'center' style= 'border:1px'>";
 echo "<tr><b>";
  echo "<td>Installation</td>";
  
  echo "<td>Area</td>";

  echo "<td>District</td>";
  
  echo "<td>Employee Name</td>";
                
                echo "<td>Reference</td>";
  
  echo "</b></tr>";
$employee = array();
 
while($row = mysql_fetch_array($result))
 {
  echo "<tr>";
  echo ("<td>$row[installation]</td>"); 
                echo ("<td>$row[area]</td>"); 
                echo ("<td>$row[district]</td>");
                echo ("<td>$row[employeename]</td>");
                echo ("<td>$row[ref]</td>"); 
  echo"</tr>";
  $employee[] = $row['employeename'];
  $arrlength = count($employee); 
 }


 echo"</table>";
 echo '<pre>'; print_r(array_filter($employee)); echo '</pre>';
?>
</body>
</html>

现在我收到这样的错误：您的 SQL 语法有误；查看与您的 MySQL 服务器版本对应的手册，了解在第 1 行的“'M.A.JINNA,K.DHANA RAJU,B.EPHRIM'”附近使用的正确语法请给我任何建议，在此先感谢 注意：由于客户要求，我不能使用员工 ID 代替员工姓名

密码是

<?
$emp = implode( ',', $employee );
echo '<pre>'; print_r($emp); echo '</pre>';

$sql = "SELECT * FROM securitystaffdetails WHERE employeename IN '" . $emp . "'";
$result = mysql_query($sql) or die(mysql_error());


echo "<table id='table1' width='1500' style= 'border:1px'>";
 echo "<tr><b>";
  echo "<td>Employee Name</td>";
  
  echo "<td>Address</td>";

  echo "<td>DOB</td>";
  
  echo "<td>Age</td>";
                
                echo "<td>SEx</td>";

  echo "<td>Mobile Number</td>";

  echo "<td>Blood Group</td>";

  echo "<td>ID Card</td>";

  echo "<td>Ex Army Idcard</td>";

  echo "<td>Police Clearence</td>";

  echo "<td>ESI Card</td>";

  echo "<td>PF Account</td>";

  echo "<td>PAN Card</td>";

  echo "<td>Voter ID</td>";

  echo "<td>Ration/Family</td>";
  
  echo "</b></tr>";
$employee = array();
 
while($record = mysql_fetch_object($result))
 {
  echo "<tr>";
  echo ("<td>$record[employeename]</td>"); 
                echo ("<td>$record[address]</td>"); 
                echo ("<td>$record[dob]</td>");
                echo ("<td>$record[age]</td>");
                echo ("<td>$record[sex]</td>");
  echo ("<td>$record[mobn]</td>");
  echo ("<td>$record[bg]</td>");
  echo ("<td>$record[icard]</td>");
  echo ("<td>$record[exarmycard]</td>");
  echo ("<td>$record[policeclearence]</td>");
  echo ("<td>$record[esicard]</td>");
  echo ("<td>$record[pfa]</td>");
  echo ("<td>$record[pancard]</td>");
  echo ("<td>$record[acard]</td>");
  echo ("<td>$record[vcard]</td>");
  echo ("<td>$record[rcard]</td>"); 
  echo"</tr>";
  
 }

 
 echo"</table>";

?>

Answer 1

将内爆线更改为：

$emp = implode( "','", $employee );

您的查询是：

"SELECT * FROM securitystaffdetails WHERE employeename IN ('" . $emp . "')";

Answer 2

你错过了 ()。

$sql = "SELECT * FROM securitystaffdetails WHERE employeename IN ('" . $emp . "')";

在 class 的地方爆炸

implode in where class

php

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