如何在 javascript 中排序

Question

如果我有这样的数组：

var tab = ['1185 Design','3 D Exhibits','44Doors', '4Concepts','ABC Data','acceleration'];

我想对其进行排序，使小写字母 'a' 元素位于大写字母 'A' 元素之前。

Answer 1

使用Array#sort() method with String#localeCompare()

var tab = ['1185 Design', '3 D Exhibits', 'nb', 'N', 'cd', '44Doors', '4Concepts', 'ABC Data', 'acceleration'];

tab.sort(function(a, b) {
  return sortFn(a, b);
});

function sortFn(a, b) {
  // if both are equal return 0
  if (a == b) return 0;
  // if first characters are equal call the same function with remaining (recursion)
  if (a.charAt(0) == b.charAt(0)) return sortFn(a.slice(1), b.slice(1))
  // check lowercase or uppercase based on that return value
  if (/^[a-z]/.test(a.charAt(0)) && /^[A-Z]/.test(b.charAt(0))) return -1;
  if (/^[a-z]/.test(b.charAt(0)) && /^[A-Z]/.test(a.charAt(0))) return 1;
  // otherwise ude normal compare function
  return a.localeCompare(b);
}

console.log(tab);

更新：如果你想按字母顺序排序，小写字母只有在它们相等时才应该有更高的优先级，然后做类似的事情。

var tab = ['1185 Design', '3 D Exhibits', 'nb', 'N', 'cd', '44Doors', '4Concepts', 'ABC Data', 'acceleration'];

tab.sort(function(a, b) {
  return sortFn(a, b);
});

function sortFn(a, b) {
  // if both are equal return 0
  if (a == b) return 0;
  // if first characters are equal call the same function with remaining (recursion)
  if (a.charAt(0) == b.charAt(0)) return sortFn(a.slice(1), b.slice(1))
  // check lowercase or uppercasebased on that return value in case the letters are equal 
  if (a.charAt(0).toLowerCase() == b.charAt(0).toLowerCase()) {
    if (/^[a-z]/.test(a.charAt(0)) && /^[A-Z]/.test(b.charAt(0))) return -1;
    if (/^[a-z]/.test(b.charAt(0)) && /^[A-Z]/.test(a.charAt(0))) return 1;
  }
  // otherwise ude normal compare function
  return a.localeCompare(b);
}


console.log(tab);

Answer 2

您可以使用 sorting with map 大小写反转。

// the array to be sorted
var list = ['1185 Design', '3 D Exhibits', '44Doors', '4Concepts', 'ABC Data', 'acceleration'];

// temporary array holds objects with position and sort-value
var mapped = list.map(function (el, i) {
    return { index: i, value: el.split('').map(function (a) {
        var b = a.toUpperCase();
        return a === b ? a.toLowerCase(): b;
    }).join('')};
});

// sorting the mapped array containing the reduced values
mapped.sort(function (a, b) {
    return +(a.value > b.value) || +(a.value === b.value) - 1;
});

// container for the resulting order
var result = mapped.map(function (el) {
    return list[el.index];
});

console.log(result);

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